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我有一个数据库,查询时可以返回有时包含网址的结果。如果结果中有地址,它将始终位于数据库的“位置”字段中。

目前,当结果返回时,它会作为一行文本返回(用户必须将其复制/粘贴到浏览器窗口中)。

如何让它返回一个超链接,而不仅仅是一行文本?

这是我的PHP...

if(mysql_num_rows($raw_results) > 0){ // if one or more rows are returned do following

            while($results = mysql_fetch_array($raw_results)){
            // $results = mysql_fetch_array($raw_results) puts data from database into array, while it's valid it does the loop

                echo "<p><strong><u><h2>".$results['SchoolName']."</h2></u></strong>".$results['text']."</p>";
                echo "<p><strong>Location:</strong>&nbsp;".$results['SchoolLocation']."".$results['text']."</p><br />";
                echo "<p><strong>Notes:</strong>&nbsp;".$results['SchoolNotes']."".$results['text']."</p><br /><br /><br />";
                // posts results gotten from database(title and text) you can also show id ($results['id'])
            }

        }
        else{ // if there is no matching rows do following

            echo "<br /><br /><br /><strong><h2>"."This is great news! The school you searched for is NOT on our Illegitimate High School List..."."</h2></strong>";
        }

    }
    else{ // if query length is less than minimum
        echo "Minimum length is ".$min_length;
    }
?>

我做了一些研究并发现了这一点,但我不知道如何将其应用于我的情况。

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1 回答 1

1

假设您来自 DB 的字段名称是 Location:

echo "<p><strong>Location:</strong>&nbsp;<a href='".$results['Location']."' target='_blank'>".$results['SchoolLocation']."</a>".$results['text']."</p><br />";
于 2013-07-23T14:57:29.150 回答