我有一个页面,我正在渲染GridView.
在 GridView 中,我有一个CheckBox
,一旦你check
,,uncheck
Jquery 对话框出现,我需要在该对话框上的回发事件。所以我在该页面上添加了手动回发。一切都很好,直到 gridview 只有 1 页。一旦 gridview 有更多记录,它就会在页面上添加一个 _doPostBack 方法。所以我现在在页面上有一个 2 _doPostBack 方法,因此没有任何效果。
我如何在我的页面中定义我不想通过任何控件添加任何 _doPostBack 方法,因为我已经手动定义了它?
这是我的 HTML
<html xmlns="http://www.w3.org/1999/xhtml">
<head id="Head1">
<title>Store Management</title>
<script src="/js/jquery-1.9.1.min.js" type="text/javascript"></script>
<script src="/js/jquery-ui.min-1.10.1.js" type="text/javascript"></script>
<link href="/assets/styles/StorePortal/style-22012013.css" rel="stylesheet"
type="text/css" />
<link href="/assets/styles/StorePortal/jquery-ui.css" rel="stylesheet"
type="text/css" />
<link href="../App_Themes/AbleCommerce/ComponentArt.css" rel="stylesheet"
type="text/css" />
<link href="../App_Themes/AbleCommerce/print.css" rel="stylesheet" type=
"text/css" />
<link href="../App_Themes/AbleCommerce/style.css" rel="stylesheet" type=
"text/css" />
<link href="../App_Themes/AbleCommerce/webparts.css" rel="stylesheet" type=
"text/css" />
</head>
<body>
<form action=
"portal.aspx?q=bbaae796d951c95311f5ec3e599784079c6093ee&q1=COV" id=
"form1" method="post" name="form1">
<div>
<input id="__EVENTTARGET" name="__EVENTTARGET" type="hidden" value=
"" /> <input id="__EVENTARGUMENT" name="__EVENTARGUMENT" type=
"hidden" value="" />
</div><script type="text/javascript">
//<![CDATA[
var theForm = document.forms['form1'];
if (!theForm) {
theForm = document.form1;
}
function __doPostBack(eventTarget, eventArgument) {
if (!theForm.onsubmit || (theForm.onsubmit() != false)) {
theForm.__EVENTTARGET.value = eventTarget;
theForm.__EVENTARGUMENT.value = eventArgument;
theForm.submit();
}
}
//]]>
</script>
<div>
<input id="__VIEWSTATEENCRYPTED" name="__VIEWSTATEENCRYPTED" type=
"hidden" value="" />
</div>
<script type="text/javascript"> --> this one is added by me manually
//<![CDATA[
var theForm = document.forms['form1'];
if (!theForm) {
theForm = document.form1;
}
function __doPostBack(eventTarget, eventArgument) {
if (!theForm.onsubmit || (theForm.onsubmit() != false)) {
theForm.__EVENTTARGET.value = eventTarget;
theForm.__EVENTARGUMENT.value = eventArgument;
theForm.submit();
}
}
//]]>
</script>
<div>
<input id="__EVENTTARGET" name="__EVENTTARGET" type="hidden" value=
"" /> <input id="__EVENTARGUMENT" name="__EVENTARGUMENT" type=
"hidden" value="" /> /// sOME CODE HERE
</div>
--> this one is added by me manually
</form>
</body>
</html>
现在,如果我删除了我添加的 _doPostBack,gridview 分页就可以工作了。但是当我在gridview 中只有一页时,我在jquery 对话框中的事件不起作用,因为它找不到_doPostBack。
回答:
我已经删除了我添加的 _doPostBack(),而是在我的 Page_Load() 上添加了它,即使没有需要此方法的 asp.net 控件,它也会添加 _doPostBack()。
ClientScript.GetPostBackEventReference(this, string.Empty);
非常感谢@Tim Schmelter 指向该链接