sql - 获取给定日期范围的总计的 SQL 语句

Question

我正在尝试获取给定日期范围内每天的预订数量及其总价值。

我的桌子看起来像：

BookingId (int)
BookingFare (decimal)
BookingDateTime (datetime)

我只能使用以下方法将 BookingDateTime 转换为日期：

SELECT CONVERT(varchar(8), BookingDateTime, 112) as BookingDateOnly
FROM   [TaxiBookingOnline].[dbo].[Bookings]

我所追求的是这样的：

Date         Bookings   Value
2013-07-10   10         256.24
2013-07-11   12         321.44
2013-07-12   14         311.53

我觉得我应该为表起别名，将其连接到自身，然后使用“GROUP BY”，但我无法让它工作。

任何帮助将非常感激。

谢谢。

Answer 1

怎么样

select
   cast(BookingDateTime as date) [Date],
   count(*) [Bookings],
   sum(BookingFare) [Value]
from t
group by cast(BookingDateTime as date)

Answer 2

SELECT   CONVERT(VARCHAR(8), BookingsDateTime, 112) AS [Date],
         COUNT(*)  AS [Bookings],
         SUM(BookingsFare AS [Value]
FROM     MyTable
GROUP BY DATEADD(dd, 0, DATEDIFF(dd, 0, BookingDateTime))

Group bySELECT DATEADD(dd, 0, DATEDIFF(dd, 0, dateColumn))将有效地获取 的日期部分datetime，然后您可以根据需要在分组值上使用countor 。sum

编辑：如果您使用的是 SQL Server >= 2008，则可以强制转换为date（就像@AlexK 所做的那样），否则您必须使用DATEADD.

Answer 3

以下是代码。将 Date1 和 Date2 替换为日期范围值：

SELECT 
CONVERT(varchar(8), BookingDateTime, 112) as BookingDateOnly, BookingID   Bookings,Sum(BookingFare)Value  
FROM 
[TaxiBookingOnline].[dbo].[Bookings]
WHERE BookingDateTime Between 'Date1' and 'Date2'
GROUP BY
BookingDateTime,BookingID

Answer 4

SELECT
    CONVERT(DATE,BookingDateTime) BookingDate,
    COUNT(BookingID) Bookings,
    SUM(BookingFare) BookingFare
FROM TaxiBookingOnline.dbo.Bookings