msbuild - 如何从命令行传递 msbuild 条件？

Question

我有一个目标作为我的构建的一部分，我希望在评估一些命令行检查时跳过它：

<Target Name="RunSomeDependencyVerification" Condition="!Exists('$(SkipVerification)')">
....

我想从控制台传递跳过验证，这样：

msbuild mybuild.dev.proj /p:SkipVerification

我的构建脚本抱怨未定义“SkipVerification”属性。我找到了文档，<PropertyGroup />但似乎不仅定义了属性，还设置了值，这不是我想要的。

我错过了什么？

score 1 · Accepted Answer

Define your property with a default value in your original msbuild file.

<PropertyGroup>
    <SkipVerification Condition="'$(SkipVerification)'==''">False</SkipVerification>
</PropertyGroup>

The "Exists" checks is not for "propertyname", whether you specified it or not. Check the VALUE of your property.

<Target Name="RunSomeDependencyVerification" Condition="'$(SkipVerification)'=='True'">

Then this.

/p:Configuration=Debug;SkipVerification=True

score 0 · Accepted Answer

Msbuild says SkipVerification is not defined because it isn't: Exists is for files or directories, not for properties. Try this instead:

msbuild mybuild.dev.proj /p:SkipVerification=true

And then check on the value:

<Target Name="RunSomeDependencyVerification"
        Condition="'$(SkipVerification)'!='true')">

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