2

我在 Android 应用程序中加密数据并将其编码以发送到 php webservice。
然后我使用它解码并解密它 $rsa->decrypt(base64_decode($data));
$rsa->解密返回假。为什么呢？

这是android中的代码

//get private key 
String privateKeyString = "MIICWwIBAAKBgQDVIJ8H3Oszc5fWdgpwymWksF1WxkXJHIfdS6Ta1bHeqwEzPIkN f3iVk14LfaoSZpRb9Yvi/jvkXxIzJbHq6aKfnQOC6tKIiixvVvpCfxr1eV4urDdz H9RNy9bqGdXzTQdgQi+KRx0Dcy9RNsl7ZGLAGrUFRnPI4GTdH+7wm4QogQIDAQAB AoGAcUcKX7KC7HDm5h0NRY+94H/AzItLsi3Q5MT81Tc5d+EqHSJysdLrs4yFMtRS 3b7Z4dqrxDVefe4uDTNe0j3lqboKz8oKwAU+paKx3wubHb7aeQnfzwM9mPQJHgEO zBjlvbL4oEa/gklu3VohZAc1daqpPajdWuOQQp4S+jUllrECQQDrITlSjvkxt8ud /vYIcEXHew3iW4nzaAH3z4PRAGZofRpk/OusGZ6cdZoYMTZcdxYTCCbZ5eeyGukW 5QCadie1AkEA6Atx8Z0F7WhLI2lGvCGy+vIOL0vBDZSma0cvLYLAXMx8duoWQ9J2 LwT7SsnRXMeq/8wlNHL7mFEf+YFZBKKlHQJAO78kfrr/zUdjwREBWaGVyZuWKpeS FTyvi1W6rAgK/bAUXeb6x69241DqyAzxQEuuW0WuAZ5u4o39/qhQH++4JQJAAepe RW1TaDNNM3yh/dmVXabz4QYSEOeiPA55YDnNFrcFbAHgryyklxzGakaiOM7ZJYVs 5TLxyr8YsXmU34nsLQJALzC8CaFXJcnU0+6+KoKX7iq1aP3X4LgP4Gianix6pfRo aV8UHnfFLRSgPdn1ZYmKtJfnsJXJYoE+o9xEErb5EQ==";

// converts the String to a PublicKey instance
KeyFactory keyFactory = KeyFactory.getInstance("RSA");
PrivateKey key = keyFactory.generatePrivate(new PKCS8EncodedKeySpec(Base64.decode(privateKeyString.toString(), Base64.DEFAULT)));

// encrypts the message
Cipher cipher = Cipher.getInstance("RSA");
cipher.init(Cipher.ENCRYPT_MODE, key);
byte[] encrpytedText = cipher.doFinal(Base64.encode(phoneUid.getBytes("CP1252"), Base64.DEFAULT));
data = new String(encrpytedText, "CP1252");



这是php中的代码

include('Crypt/RSA.php');
$rsa = new Crypt_RSA();
//Set the encryption mode
$rsa->setEncryptionMode(CRYPT_RSA_ENCRYPTION_PKCS1);

//check for required fields
if (isset($_POST['data']) {
$data= $_POST['data'];
$key =  '-----BEGIN PUBLIC KEY-----
MIGfMA0GCSqGSIb3DQEBAQUAA4GNADCBiQKBgQDVIJ8H3Oszc5fWdgpwymWksF1W xkXJHIfdS6Ta1bHeqwEzPIkNf3iVk14LfaoSZpRb9Yvi/jvkXxIzJbHq6aKfnQOC 6tKIiixvVvpCfxr1eV4urDdzH9RNy9bqGdXzTQdgQi+KRx0Dcy9RNsl7ZGLAGrUF RnPI4GTdH+7wm4QogQIDAQAB
-----END PUBLIC KEY-----';

$rsa->loadKey($key );
$decrypted = $rsa->decrypt(base64_decode($data));
4

2 回答 2

1

我解决了我的问题。这是那些和我做类似事情的人的参考。希望这对其他人有所帮助。

在android中（RSA用私钥加密）

String encoded = null;
byte[] encrypted = null;
String plaintext = "...";

try {
    String privKeyPEM = "...";
    byte[] decoded = Base64.decode(privKeyPEM, Base64.DEFAULT);
    PKCS8EncodedKeySpec spec = new PKCS8EncodedKeySpec(decoded);
    KeyFactory kf = KeyFactory.getInstance("RSA");
    PrivateKey privKey = kf.generatePrivate(spec);

    Cipher cipher = Cipher.getInstance("RSA/ECB/PKCS1Padding");
    cipher.init(Cipher.ENCRYPT_MODE, privKey);

    encrypted = cipher.doFinal(plaintext.getBytes());
    encoded = Base64.encodeToString(encrypted, Base64.DEFAULT);
}
catch (Exception e) {
    e.printStackTrace();
}

在 PHP 中（使用公钥解密）（使用 phpseclib）

$publickey = '...';    
$rsa = new Crypt_RSA();
$rsa->setEncryptionMode(CRYPT_RSA_ENCRYPTION_PKCS1);

//decode and decrypt
$decoded =  base64_decode($encrypted);
$rsa->loadKey($publickey);
$decrypted = $rsa->decrypt($decoded);
于 2013-07-25T13:54:48.067 回答
0

您是否将正确的参数传递给 cipher.doFinal？

引用javadoc 条目：

doFinal(byte[] inBuff, short inOffset, short inLength, byte[] outBuff, short outOffset)

此外，当您应该在加密后加密密文时，看起来您在加密之前对明文进行 base64 编码？

于 2013-07-22T19:33:57.700 回答