2

i have found this simple jQuery code for a slideshow below from this blog.

http://leavesofcode.net/2012/08/17/simple-slideshow/

It perfectly works in the project i am working on right now, where i can call the images with jQuery load() function and the slideshow still works. Although i would like to implement a previous and next button in the same code if its possible. Any help would be really appreciated. Please help thanks.

Here is the code: http://jsfiddle.net/mblase75/CRUJJ/

<script>
$(document).ready(function() {
    setInterval(function() {
        var $curr = $('.slideshow img:visible'), // should be the first image
            $next = ($curr.next().length) ? $curr.next() : $('.slideshow img').first();
            // if there isn't a next image, loop back to the first image
        $next.css('z-index',2).fadeIn('slow', function() { // move it to the top
            $curr.hide().css('z-index',0); // move this to the bottom
            $next.css('z-index',1);        // now move it to the middle
        });
    }, 6000); // milliseconds
});
</script>

<div class="slideshow">
    <img src="first-image.jpg" width="500" height="100" alt="first image">
    <img src="second-image.jpg" width="500" height="100" alt="second image">
    <img src="third-image.jpg" width="500" height="100" alt="third image">
    <img src="fourth-image.jpg" width="500" height="100" alt="fourth image">
</div>

<style>
.slideshow {
    position: relative; /* necessary to absolutely position the images inside */
    width: 500px; /* same as the images inside */
    height: 100px;
}
.slideshow img {
    position: absolute;
    display: none;
}
.slideshow img:first-child {
    display: block; /* overrides the previous style */
}
</style>
4

6 回答 6

6

您需要为 getNext 和 getPrev 创建函数，并将它们作为事件处理程序附加到要在幻灯片中前后移动的元素。

我创建了一个由 getNext 和 getPrev 函数共享的通用转换函数，以便可以共享转换代码。

在下面的示例中，单击下一个或上一个按钮将暂停幻灯片，但很容易更改它以继续自动转换。

工作演示

var interval = undefined;
$(document).ready(function () {
    interval = setInterval(getNext, 2000); // milliseconds
    $('#next').on('click', getNext);
    $('#prev').on('click', getPrev);
});

function getNext() {
    var $curr = $('.slideshow img:visible'),
        $next = ($curr.next().length) ? $curr.next() : $('.slideshow img').first();

    transition($curr, $next);
}

function getPrev() {
    var $curr = $('.slideshow img:visible'),
        $next = ($curr.prev().length) ? $curr.prev() : $('.slideshow img').last();
    transition($curr, $next);
}

function transition($curr, $next) {
    clearInterval(interval);

    $next.css('z-index', 2).fadeIn('slow', function () {
        $curr.hide().css('z-index', 0);
        $next.css('z-index', 1);
    });
}
于 2013-07-22T12:10:15.153 回答
1

我知道这很旧，但请更正以下内容：

$('.slideshow :first-child').fadeOut(1000).next('img').fadeIn(1000).end().appendTo('#slideshow');

.slideshow {
    width: 100%;
    position: relative;
    height: auto;
}
.slideshow img:first-child { position:relative; } /*auto height adjust*/
.slideshow img {
    top: 0;
    left: 0;
    width: 100%;
    max-width: 600px;
    height: auto;
    position: absolute;
}

只是想反其道而行之。以上都很好，但是过渡，呃，不流畅。在这个上使用类是有原因的。

于 2013-12-16T22:57:20.063 回答
1

在您的 HTML 中添加几个 img，如下所示：

<div class="slideshow">
    <img src="first-image.jpg" width="500" height="100" alt="first image">
    <img src="second-image.jpg" width="500" height="100" alt="second image">
    <img src="third-image.jpg" width="500" height="100" alt="third image">
    <img src="fourth-image.jpg" width="500" height="100" alt="fourth image">
</div>
<img src="prev.jpg" width="50" height="50" id="imgPrev">
<img src="next.jpg" width="50" height="50" id="imgNext">

并像这样更改您的javascript：

    $(document).ready(function() {

        $("#imgNext").click(function() {
             var $curr = $('.slideshow img:visible'),
                 $next = ($curr.next().length) ? $curr.next() : $('.slideshow img').first();
                $next.css('z-index',2).fadeIn('slow', function() {
                $curr.hide().css('z-index',0);
                $next.css('z-index',1);
            });
    });

        $("#imgPrev").click(function() {
             var $curr = $('.slideshow img:visible'),
                 $prev = ($curr.prev().length) ? $curr.prev() : $('.slideshow img').last();
                $prev.css('z-index',2).fadeIn('slow', function() {
                $curr.hide().css('z-index',0);
                $prev.css('z-index',1);
            });
        });

        set

Interval(function() {
        var $curr = $('.slideshow img:visible'), 
            $next = ($curr.next().length) ? $curr.next() : $('.slideshow img').first();
        $next.css('z-index',2).fadeIn('slow', function() {
            $curr.hide().css('z-index',0);
            $next.css('z-index',1);
        });
    }, 6000); // milliseconds
});

我在提琴手上用你的代码试过它，它可以工作:)

于 2013-07-22T12:10:18.920 回答
1

在下一个按钮的单击事件中使用您的代码。像这样的东西：

    $("#button_id").click(function(){
all your lines in **setInterval**
});

对于上一个按钮，使用.prev而不是.next

于 2013-07-22T11:55:59.510 回答
1

响应式幻灯片免费 jquery 脚本

我最近在一个项目中使用了上面的脚本，它响应迅速、轻量级、完全可定制，带或不带按钮。我的推荐..

于 2013-07-22T11:57:41.907 回答
0

尝试

 $('.next').click(function(){ 
     $('#slideshow img:first').fadeOut(1000).next().fadeIn(1000).end().appendTo('#slideshow');
   })
于 2013-07-22T11:54:38.940 回答