1

比如说,我有以下 WIX 标记,指示 MSI 安装程序从包含的 DLL 调用自定义操作:

<CustomAction Id="CA_SetProperties_Finalize" 
        Property="CA_OnInstallFinalize" 
           Value="[Installed],[REINSTALL],[UPGRADINGPRODUCTCODE],[REMOVE]" />

<CustomAction Id='CA_OnInstallFinalize' 
       BinaryKey='CADll' 
        DllEntry='msiOnInstallFinalize' 
         Execute='deferred' Impersonate='no' />

<InstallExecuteSequence>
  <Custom Action='CA_SetProperties_Finalize' 
          Before='InstallFinalize'></Custom>
  <Custom Action='CA_OnInstallFinalize' 
           After='CA_SetProperties_Finalize'></Custom>
</InstallExecuteSequence>

<Binary Id='CADll' SourceFile='Sources\ca-installer.dll' />

并且 DLL 本身具有以下用于自定义操作的 C++ 代码:

#pragma comment(linker, "/EXPORT:msiOnInstallFinalize=_msiOnInstallFinalize@4")

extern "C" UINT __stdcall msiOnInstallFinalize(MSIHANDLE hInstall) 
{
    //Do the work
    if(doWork(hInstall) == FALSE)
    {
        //Error, cannot continue!
        return ERROR_INSTALL_FAILURE;
    }

    return ERROR_SUCCESS;
}

发生的情况是,当我的doWork方法失败时,安装不应该继续,所以我返回ERROR_INSTALL_FAILURE. 问题是,在这种情况下,安装程序会简单地退出并且安装 GUI 窗口会消失。

所以我很好奇,如果我的自定义操作返回错误,有什么方法可以更改 Wix 标记以显示用户消息?

4

3 回答 3

4

我用它来创建消息框来处理我的 dll 中的错误:

PMSIHANDLE hRecord = MsiCreateRecord(0);
MsiRecordSetString(hRecord, 0, TEXT("Enter the text for the error!"));
MsiProcessMessage(hInstall, INSTALLMESSAGE(INSTALLMESSAGE_ERROR + MB_OK), hRecord);
return ERROR_INSTALL_USEREXIT;
于 2013-07-22T14:24:09.130 回答
2

我能够将该代码转换为 VB.NET 并在自定义操作中使用它来显示错误弹出窗口

.Net 代码看起来明显不同

Private Shared Sub DisplayMSIError(session As Session, msg As String)
  Dim r As New WindowsInstaller.Record(0)
  r.SetString(0, msg)
  session.Message(InstallMessage.Error, r)
End Sub

我还在 MSDN 上发现它使用 vbscript http://msdn.microsoft.com/en-us/library/xc8bz3y5(v=vs.80).aspx

于 2013-07-31T13:43:17.887 回答
2

对于 C# 用户...

                string msg = "XXXXXX code is invalid";
                Record r = new Microsoft.Deployment.WindowsInstaller.Record(0);
                r.SetString(0, msg);
                session.Message(InstallMessage.Error, r);
                session.Log(msg);
于 2019-04-19T19:28:39.127 回答