git - 在 bash 脚本中按模式过滤行

Question

我有两个变量，一个带有文本，另一个带有模式。我想过滤掉线条，匹配的模式。我怎样才能做到这一点？

我的脚本看起来像这样

# get ignore files list
IGNORE=`cat ignore.txt`

# get changed files list
CHANGED=`git diff --name-only $LAST_COMMIT HEAD`

# remove files, that should be ignored from change list
for IG in $IGNORE; do
    echo $CHANGED
    $CHANGED=`cat $CHANGED | grep -v $IG`
done

Answer 1

您可以将模式文件直接提供给 grep

# get changed files list and remove files that should be ignored
CHANGED=$(git diff --name-only $LAST_COMMIT HEAD | grep -vf ignore.txt)
echo $CHANGED

（我建议使用$()而不是反引号。）

---

顺便说一句，这一行：

$CHANGED=`cat $CHANGED | grep -v $IG`

应该看起来像这样：

CHANGED=`echo $CHANGED | grep -v $IG`

如果你要保留它。

Answer 2

# Disable globbing
set -f
# Collect variables
IGNORE=$(cat ignore.txt)
CHANGED=$(...)

# Apply each pattern in turn
for pattern in $IGNORE
do
    # Reset the current list of candidates
    CANDIDATES=
    for candidate in $CHANGED
    do
        # Apply the pattern
        CANDIDATES="$CANDIDATES ${candidate%$pattern}"
    done
    # Update the CHANGED list
    CHANGED=$CANDIDATES
done