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我有一个我创建的列表。我正在上传一些数据，然后将其绑定到gridview。代码如下。

private void button7_Click(object sender, EventArgs e)
    {
        List<MyColumns> list = new List<MyColumns>();

        OpenFileDialog openFile1 = new OpenFileDialog();
        openFile1.Multiselect = true;

        if (openFile1.ShowDialog() != DialogResult.Cancel)
        {
            foreach (string filename in openFile1.FileNames)
            {
                using (StreamReader sr = new StreamReader(filename))
                {
                    string line;
                    while ((line = sr.ReadLine()) != null)
                    {
                        string[] _columns = line.Split(",".ToCharArray());
                        MyColumns mc = new MyColumns();
                        mc.Time = _columns[0];
                        mc.System_Description = _columns[1];
                        mc.User_Description = _columns[2];
                        list.Add(mc);
                    }
                }
            }
            DataTable ListAsDataTable = BuildDataTable<MyColumns>(list);
            DataView ListAsDataView = ListAsDataTable.DefaultView;
            this.dataGridView1.DataSource = view = ListAsDataView;
            this.dataGridView1.AllowUserToAddRows = false;
            dataGridView1.ClearSelection();
        }
    }



class MyColumns
{
    public string Time { get; set; }
    public string System_Description { get; set; }
    public string User_Description { get; set; }
}

我的问题是是否可以从 System_Description 列访问数据？我想对此数据进行一些更改。我的意思是我想像这 3 列一样正常显示它，但可能保存在另一个列表更改版本的列 System_Description 中？

4

1 回答 1

2

你可以这样做

List<string> description = youroriginalList
                          .Select(x=>x.System_Description).ToList<string>();
于 2013-07-20T17:13:50.243 回答