ios - 再次显示 UImage - 滑动删除 Ios -

Question

我正在使用滑动删除功能

- (void)tableView:(UITableView *)tableView commitEditingStyle:(UITableViewCellEditingStyle)editingStyle forRowAtIndexPath:(NSIndexPath *)indexPath {

if (editingStyle == UITableViewCellEditingStyleDelete) {
    //add code here for when you hit delete
    NSLog(@"UITableViewCellEditingStyleDelete");
    [liste removeObjectAtIndex:indexPath.row];
    [self refreshTableView];
}
}

我需要在选定的单元格上隐藏一个 UImage，所以我正在使用这段代码

    - (void)tableView:(UITableView*)tableView willBeginEditingRowAtIndexPath:(NSIndexPath *)indexPath;{   
cellTodelete = (ListeRestoCell *) [self.tableView cellForRowAtIndexPath:indexPath];
if(cellTodelete.eventImage.hidden==NO) {
    a = 1 ;
    cellTodelete.eventImage.hidden = YES ;
}    
return;
}

这项工作很棒，唯一的问题是即使未单击删除按钮，我的 Uimage 也会隐藏，因此如果未单击删除按钮，我需要再次显示图像。我怎样才能做到这一点？

Answer 1

这样做，

在.h

BOOL isDeleted;
NSIndexPath *selIndexPath;

在.m loadView

 isDeleted = NO;

/

 - (void)tableView:(UITableView*)tableView willBeginEditingRowAtIndexPath:(NSIndexPath *)indexPath;{   

 selIndexPath = indexPath;
cellTodelete = (ListeRestoCell *) [self.tableView cellForRowAtIndexPath:indexPath];
if(cellTodelete.eventImage.hidden==NO) {
    a = 1 ;
    cellTodelete.eventImage.hidden = YES ;
}    
return;
}

/

- (void)tableView:(UITableView *)tableView commitEditingStyle:(UITableViewCellEditingStyle)editingStyle forRowAtIndexPath:(NSIndexPath *)indexPath {

if (editingStyle == UITableViewCellEditingStyleDelete) {   

    isDeleted = YES;
    //add code here for when you hit delete
    NSLog(@"UITableViewCellEditingStyleDelete");
    [liste removeObjectAtIndex:indexPath.row];
    [self refreshTableView];
}
}

/

- (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath
{


      if(!isDeleted && selIndexPath!=nil) {

           cellTodelete = (ListeRestoCell *) [self.tableView cellForRowAtIndexPath:selIndexPath];
           cellTodelete.eventImage.hidden = NO ;
      }

}