4

Win 8 似乎有一个新的用户组“ALL APPLICATION PACKAGES”。默认情况下，该组似乎对所有文件夹都具有读取权限。但是我的要求是在我创建的文件夹上设置一些特定的 ACL。该组目前对我的文件夹没有权限，我编写了一些代码来添加“所有应用程序包”的读取权限。我正在使用 VS 2010，下面是精简的代码片段。

在http://msdn.microsoft.com/en-us/library/cc980032.aspx中列出的“所有应用程序包”的 SID是 ALL_APP_PACKAGES (S-1-15-2-1)。

但无论我作为受托人名称传递的值如何或传递什么值，下面的代码都不起作用。例如，在下面的代码中 SetNamedSecurityInfo() 失败并显示 ERROR_INVALID_ACL。但是，如果我使用“管理员”或“所有人”帐户，那么它可以工作。

我需要分配的确切权限是“读取和执行”、“列出文件夹内容”和“读取”</p> 

#include "stdafx.h"
#include "windows.h"
#include "sddl.h"
#include "Aclapi.h"

int _tmain(int argc, _TCHAR* argv[])
{
TCHAR pszObjName[MAX_PATH] = L"C:\\Program Files\\Common Files\\Test\\";
PACL pOldDACL = NULL, pNewDACL = NULL;
PSECURITY_DESCRIPTOR pSD = NULL;
EXPLICIT_ACCESS ea;
SECURITY_INFORMATION si = DACL_SECURITY_INFORMATION;

// Get a pointer to the existing DACL (Conditionaly).
DWORD dwRes = GetNamedSecurityInfo(pszObjName, SE_FILE_OBJECT, DACL_SECURITY_INFORMATION, NULL, NULL, &pOldDACL, NULL, &pSD);

// Initialize an EXPLICIT_ACCESS structure for the new ACE. 
ZeroMemory(&ea, sizeof(EXPLICIT_ACCESS));
ea.grfAccessPermissions = STANDARD_RIGHTS_READ;
ea.grfAccessMode = SET_ACCESS;
ea.grfInheritance= SUB_CONTAINERS_AND_OBJECTS_INHERIT;
ea.Trustee.TrusteeForm = TRUSTEE_IS_SID;
// ea.Trustee.TrusteeType = TRUSTEE_IS_GROUP;
// Should I be using SID (S-1-15-2-1) (SetEntriesInAcl() fails) or "ALL_APP_PACKAGES" (SetEntriesInAcl() passes but SetNamedSecurityInfo() fails)
//If I use "Administrators" or "Everyone" as Trustee Name then it works fine but not with "ALL APPLICATION PACKAGES"
ea.Trustee.ptstrName = _T(" ALL_APP_PACKAGES"); 

// Create a new ACL that merges the new ACE into the existing DACL.
dwRes = SetEntriesInAcl(1, &ea, pOldDACL, &pNewDACL);
if(ERROR_SUCCESS != dwRes) 
goto Cleanup; 

// Attach the new ACL as the object's DACL.
dwRes = SetNamedSecurityInfo(pszObjName, SE_FILE_OBJECT, si, NULL, NULL, pNewDACL, NULL);
if(ERROR_SUCCESS != dwRes)  
goto Cleanup;

Cleanup:
if(pSD != NULL) 
LocalFree((HLOCAL) pSD); 
if(pNewDACL != NULL) 
LocalFree((HLOCAL) pNewDACL); 

return dwRes;
}
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2 回答 2

5

尝试以这种方式设置受托人结构。这个对我有用。

ea.Trustee.TrusteeForm = TRUSTEE_IS_NAME;
ea.Trustee.TrusteeType = TRUSTEE_IS_WELL_KNOWN_GROUP;
ea.Trustee.ptstrName = L"ALL APPLICATION PACKAGES";
于 2013-08-07T13:28:41.767 回答
4

我需要分配的确切权限是“读取和执行”、“列出文件夹内容”和“读取”所以你需要

ea.grfAccessPermissions = GENERIC_READ | GENERIC_EXECUTE;

代替

ea.grfAccessPermissions = STANDARD_RIGHTS_READ;

如果组名已本地化，这也可能不起作用：

ea.Trustee.TrusteeForm = TRUSTEE_IS_NAME;
ea.Trustee.TrusteeType = TRUSTEE_IS_WELL_KNOWN_GROUP;
ea.Trustee.ptstrName = L"ALL APPLICATION PACKAGES";

这件作品将：

// Allocate enough memory for the largest possible SID.
PSID TheSID = NULL;
DWORD SidSize = SECURITY_MAX_SID_SIZE;
if (!(TheSID = LocalAlloc(LMEM_FIXED, SidSize)))
    goto Cleanup;

// Create a SID for the Everyone group on the local computer.
if (!CreateWellKnownSid(WinBuiltinAnyPackageSid, NULL, TheSID, &SidSize))
    goto Cleanup;

// Initialize an EXPLICIT_ACCESS structure for the new ACE. 
ZeroMemory(&ea, sizeof(EXPLICIT_ACCESS));
ea.grfAccessPermissions = GENERIC_READ | GENERIC_EXECUTE;
ea.grfAccessMode = SET_ACCESS;
ea.grfInheritance = SUB_CONTAINERS_AND_OBJECTS_INHERIT;
ea.Trustee.TrusteeForm = TRUSTEE_IS_SID;
ea.Trustee.TrusteeType = TRUSTEE_IS_WELL_KNOWN_GROUP;
ea.Trustee.ptstrName = (LPWSTR)TheSID;
于 2015-08-05T09:38:20.900 回答