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我需要解析 twitter 用户提要，我正在尝试从 json 字符串制作 JSON 对象。我能够正确获取 json 字符串，但是当我尝试从中创建 JSON 对象时，它显示JSONException. 这是我的尝试代码。

package com.heath_bar.twitter;

import java.io.BufferedReader;
import java.io.InputStream;
import java.io.InputStreamReader;

import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.client.methods.HttpGet;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.entity.StringEntity;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.params.BasicHttpParams;
import org.json.JSONArray;
import org.json.JSONException;
import org.json.JSONObject;

import android.app.Activity;
import android.os.AsyncTask;
import android.os.Bundle;
import android.util.Base64;
import android.util.Log;
import android.view.Menu;
import android.view.View;
import android.view.View.OnClickListener;
import android.widget.Button;
import android.widget.TextView;

public class MainActivity extends Activity {

    final String URL = "https://api.twitter.com/1.1/statuses/user_timeline.json?screen_name=*******";
    final String APIKEY = "***********************";
    final String APISECRET = "*********************";
    final String BearerToken = "AAAAAAAAAAAAAAAAAAAAAMRF***************************";

    JSONObject jsonObj = null;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
        Button btn_get_feed = (Button) findViewById(R.id.btn_get_feed);
        btn_get_feed.setOnClickListener(new OnClickListener() {
            @Override
            public void onClick(View v) {
                String bearer_token = BearerToken;
                new GetFeedTask().execute(bearer_token, URL);
            }
        });
    }

    protected class GetFeedTask extends AsyncTask<String, Void, String> {

        @Override
        protected String doInBackground(String... params) {

            try {
                DefaultHttpClient httpclient = new DefaultHttpClient(
                        new BasicHttpParams());
                HttpGet httpget = new HttpGet(params[1]);
                httpget.setHeader("Authorization", "Bearer " + params[0]);
                httpget.setHeader("Content-type", "application/json");

                InputStream inputStream = null;
                HttpResponse response = httpclient.execute(httpget);
                HttpEntity entity = response.getEntity();
                inputStream = entity.getContent();
                BufferedReader reader = new BufferedReader(new InputStreamReader(
                        inputStream, "iso-8859-1"), 8);
                StringBuilder sb = new StringBuilder();
                String line = null;
                while ((line = reader.readLine()) != null) {
                    sb.append(line + "\n");
                }
                inputStream.close();
                return sb.toString();
            } catch (Exception e) {
                Log.e("GetFeedTask", "Error:" + e.getMessage());
                return null;
            }
        }

        @Override
        protected void onPostExecute(String jsonText) {
            try {
                TextView txt = (TextView) findViewById(R.id.txt_feed);
                txt.setText(jsonText); // this is showing the JSON string

                try {
                    jsonObj = new JSONObject(jsonText);
                    Log.d("status_success", "Successfully created JSON object");
                } catch (JSONException e) {
                    Log.e("JSON Parser", "Error parsing data " + e.toString());
                }
            } catch (Exception e) {
                Log.e("GetFeedTask", "Error:" + e.getMessage());
            }
        }
    }

}
4

2 回答 2

1

I need to parse twitter feed.......

尝试JSONArray代替JSONObject.

JSONArray jsonArray = new JSONArray(jsonText);

Twitter REST API 1.1提要以数组节点开始。可以在此处找到示例 twitter JSON 提要。

[
  {
    "coordinates": null,
    "favorited": false,
    "truncated": false,
    "created_at": "Wed Aug 29 17:12:58 +0000 2012",
    "id_str": "240859602684612608",
    "entities": {
      "urls": [
        {
          "expanded_url": "https://dev.twitter.com/blog/twitter-certified-products",
          "url": "https://t.co/MjJ8xAnT",
          "indices": [
            52,
            73
          ],
          "display_url": "dev.twitter.com/blog/twitter-c\u2026"
        }
      ],
      "hashtags": [

      ],
      "user_mentions": [

      ]
    },
    "in_reply_to_user_id_str": null,
    "contributors": null,
    "text": "Introducing the Twitter Certified Products Program: https://t.co/MjJ8xAnT",
    "retweet_count": 121,
    "in_reply_to_status_id_str": null,
    "id": 240859602684612608,
    "geo": null,
    "retweeted": false,
    "possibly_sensitive": false,
    "in_reply_to_user_id": null,
    "place": null,
    "user": {
      "profile_sidebar_fill_color": "DDEEF6",
      "profile_sidebar_border_color": "C0DEED",
      "profile_background_tile": false,
      "name": "Twitter API",
      "profile_image_url": "http://a0.twimg.com/profile_images/2284174872/7df3h38zabcvjylnyfe3_normal.png",
      "created_at": "Wed May 23 06:01:13 +0000 2007",
      "location": "San Francisco, CA",
      "follow_request_sent": false,
      "profile_link_color": "0084B4",
      "is_translator": false,
      "id_str": "6253282",
      "entities": {
        "url": {
          "urls": [
            {
              "expanded_url": null,
              "url": "http://dev.twitter.com",
              "indices": [
                0,
                22
              ]
            }
          ]
        },
        "description": {
          "urls": [

          ]
        }
   }
]
于 2013-07-20T08:53:51.720 回答
1

Twitter 推文位于每个 JSONObject 的“文本”标签下。从 json 数组访问每个 json 对象，如下所示

ArrayList<String> tweets=new ArrayList<String>();
JSONArray array =new JSONArray(jsonText);
                    for(int i=0;i<array.length();i++){
                        JSONObject obj=array.getJSONObject(i);
                        String text=obj.getString("text");
                        tweets.add(text);
                        ArrayAdapter<String> adapter=new ArrayAdapter<String>(getBaseContext(),android.R.layout.simple_list_item_1,tweets);
                        lv.setAdapter(adapter);// displaying in a listview
                    }
于 2013-07-20T09:14:15.823 回答