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我有这个查询：

SELECT `ca`.*, `a`.* FROM `container_asset` AS `ca` LEFT JOIN `asset` AS `a` ON ca.asset_id = a.id WHERE `container_id` = '4' AND `deleted` = '0' AND `reason` IN ('main', 'previous_version') ORDER BY `reason` ASC, `asset_id` DESC

我希望返回两行，但是当我使用此命令执行查询时：

$conn =new  \mysqli('localhost', 'root', '12345', 'assetdb') or die("Error " . mysqli_error($link));
$res3 = $conn->query("SELECT `ca`.*, `a`.* FROM `container_asset` AS `ca` LEFT JOIN `asset` AS `a` ON ca.asset_id = a.id WHERE `container_id` = '4' AND `deleted` = '0' AND `reason` IN ('main', 'previous_version') ORDER BY `reason` ASC, `asset_id` DESC");
while ($r = mysqli_fetch_array($res3))
        {
            echo $r['id']."\n";
        }

它在获取结果时返回 1 行但是当我直接执行查询时（在 heidisql 或 phpmyadmin 中）它返回预期的结果，2 行。

我无法解释这个问题？

编辑

我做了更多测试，如果我期望 5 行它返回 4，所以它返回 1 行。

编辑2

数据：container_asset 表，asset_id 在asset->id 中的外键：

“container_id” “asset_id” “原因”
“1”“2”“主要”
“2”“1”“主要”
“3” “3” “主要”
"4" "3" "previous_version"
“4”“4”“主要”

资产表

“id” “asset_class” “已删除” “file_name”
"1" "视频" "0" "ÄÖ.jpg"
"2" "图片" "0" "èungrandeguitar.jpg"
“3”“图像”“0”“3.jpg”
"4" "图片" "0" "çàù.jpg"

编辑 3

即使我删除了加入，结果仍然是错误的：

SELECT `ca`.* FROM `container_asset` AS `ca` WHERE ca.`container_id` = '4'  AND `reason` IN ('main', 'previous_version') ORDER BY `reason` ASC, `asset_id` DESC
4

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