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我正在尝试为单击时返回其值的按钮分配值（更准确地说，它们打印它。）唯一需要注意的是按钮是使用 for 循环动态创建的。

如何将 id（和其他变量）分配给使用 for 循环创建的按钮？

示例代码：

#Example program to illustrate my issue with dynamic buttons.

from Tkinter import *

class my_app(Frame):
    """Basic Frame"""
    def __init__(self, master):
        """Init the Frame"""
        Frame.__init__(self,master)
        self.grid()
        self.Create_Widgets()

    def Create_Widgets(self):

        for i in range(1, 11): #Start creating buttons

            self.button_id = i #This is meant to be the ID. How can I "attach" or "bind" it to the button?
            print self.button_id

            self.newmessage = Button(self, #I want to bind the self.button_id to each button, so that it prints its number when clicked.
                                     text = "Button ID: %d" % (self.button_id),
                                     anchor = W, command =  lambda: self.access(self.button_id))#Run the method

            #Placing
            self.newmessage.config(height = 3, width = 100)
            self.newmessage.grid(column = 0, row = i, sticky = NW)

    def access(self, b_id): #This is one of the areas where I need help. I want this to return the number of the button clicked.
        self.b_id = b_id
        print self.b_id #Print Button ID

#Root Stuff


root = Tk()
root.title("Tkinter Dynamics")
root.geometry("500x500")
app = my_app(root)

root.mainloop()
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1 回答 1

8

问题是您使用的self.button_id是创建按钮后调用命令时的最后一个值。您必须将每个 lambda 的局部变量的当前值绑定到lambda i=i: do_something_with(i)：

def Create_Widgets(self):
    for i in range(1, 11):
        self.newmessage = Button(self, text= "Button ID: %d" % i, anchor=W,
                                 command = lambda i=i: self.access(i))
        self.newmessage.config(height = 3, width = 100)
        self.newmessage.grid(column = 0, row = i, sticky = NW)
于 2013-07-20T00:56:05.803 回答