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如何将以下 Python PuLP 语句简化为更 Pythonic、易于管理和正确的语句:

import pulp as lp

#delare variables
#Note that I have to model a 100 year period!
year_1 = lp.LpVariable("2011", 0, None, lp.LpInteger)    
year_2 = lp.LpVariable("2012", 0, None, lp.LpInteger)
year_. = lp.LpVariable("201.", 0, None, lp.LpInteger)
year_n = lp.LpVariable("201n", 0, None, lp.LpInteger)

#declare constraints
prob += year_1 - year_0 >= 0
prob += year_2 - year_1 >= 0
prob += year_. - year_. >= 0
prob += year_n - year_n_1 >= 0
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1 回答 1

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列出年份而不是 100 年的变量:

years = [lp.LpVariable(str(2011+i), 0, None, lp.LpInteger) for i in xrange(n)]

请注意,列表是 0 索引的,所以以前year_1是 now years[0]

您可以遍历它以获取脚本的“声明约束”部分:

for year, next_year in zip(years[:-1], years[1:]):
    prob += next_year - year >= 0
于 2013-07-19T20:10:15.830 回答