0

我正在使用以下查询：

<?php
 // retrieve products from database
 global $db;
$q1 = $db->Execute("select * from products");
$q1_items = array();
$q2_items = array();

while (!$q1->EOF){
$q1_items[] = $q1->fields;
$q1->MoveNext();
}
foreach ($q1_items as $item => $items) {
echo '<p><a href="index.php?main_page=product_info&products_id='. $items['products_id'] .'"><img src="images/'. $items['products_image'].'" alt="'. $items['products_name'].'" title="'. $items['products_name'].'" /></a>';
    echo ''.$items['products_price']. ''; ?>

<?php }
?>

我遇到的问题是它没有提取产品名称，我希望能够从 TABLE_PRODUCTS_DESCRIPTION 和 Products_attributes 中查询每个 product_description。

4

1 回答 1

0

这是因为 products_name 和 products_description 在表 products_description 中（或者更具体地在 TABLE_PRODUCTS_DESCRIPTION 中），而不是在表 products (TABLE_PRODUCTS) 中。

要获取所有基本信息（属性除外），您应该执行以下查询：

$q = $db->Execute("SELECT * FROM " . TABLE_PRODUCTS . " p LEFT JOIN " . TABLE_PRODUCTS_DESCRIPTION . " pd ON(p.products_id = pd.products_id) WHERE language_id = " . (int)$_SESSION['languages_id']);
$items = array();
while(!$q->EOF) {
    // let's get all attribues for product
    $productInfo = $q->fields;
    $qattr = $db->Execute("SELECT * FROM " . TABLE_PRODUCTS_ATTRIBUTES . " WHERE products_id = " . (int)$q->fields['products_id']);
    $attr = array();
    while(!$qattr->EOF) {
        $attr[] = $qattr->fields;
        $qattr->MoveNext();
    }
    $productInfo['attributes'] = $attr;
    $items[] = $productInfo;
    $q->MoveNext();
}

// now let's output it
foreach($items as $item) {
    echo '<p><a href="index.php?main_page=product_info&products_id='. $item['products_id'] .'"><img src="images/'. $item['products_image'].'" alt="'. $item['products_name'].'" title="'. $items['products_name'].'" /></a>';
    echo $items['products_price'] . '</p>';
}

但是请注意，此代码不获取特定类别的产品 - 它获取所有产品，甚至那些已停用的产品。有几种方法可以从特定类别中获取产品，但它们的性能各不相同。不幸的是，没有最好的方法来做到这一点，因为它取决于数据。如果您希望检索的产品属于 category_id 为 5 的类别并且它是它们的主要类别，则添加到第一个查询“WHERE master_categories_id = 5”就足够了。但是，如果类别不是这些产品的主类别，事情会变得更加复杂，因为我们需要访问 products_to_categories 表，这会导致具有许多产品的网站的性能受到影响。如果您不太了解/不太关心性能，您可以将第一个查询更改为：（假设您已经知道您的类别的 categories_id）：

$q = $db->Execute("SELECT * FROM " . TABLE_PRODUCTS . " p LEFT JOIN " . TABLE_PRODUCTS_DESCRIPTION . " pd ON(p.products_id = pd.products_id LEFT JOIN " . TABLE_PRODUCTS_TO_CATEGORIES . " p2c ON(p.products_id = p2c.products_id AND p2c.categories_id = YOUR_CATEGORY_ID) WHERE pd.products_id IS NOT NULL AND p2c.products_id IS NOT NULL AND language_id = " . (int)$_SESSION['languages_id']);

摆脱不活跃的产品执行

$q = $db->Execute("SELECT * FROM " . TABLE_PRODUCTS . " p LEFT JOIN " . TABLE_PRODUCTS_DESCRIPTION . " pd ON(p.products_id = pd.products_id LEFT JOIN " . TABLE_PRODUCTS_TO_CATEGORIES . " p2c ON(p.products_id = p2c.products_id AND p2c.categories_id = YOUR_CATEGORY_ID) WHERE products_status = 1 AND pd.products_id IS NOT NULL AND p2c.products_id IS NOT NULL AND language_id = " . (int)$_SESSION['languages_id']);

（实际上不需要检查 pd.products_id IS NOT NULL 因为我们已经检查了 pd.language_id。）

没有属性的编辑版本

$q = $db->Execute("SELECT * FROM " . TABLE_PRODUCTS . " p LEFT JOIN " . TABLE_PRODUCTS_DESCRIPTION . " pd ON(p.products_id = pd.products_id) WHERE language_id = " . (int)$_SESSION['languages_id']);
$items = array();
while(!$q->EOF) {
    $items[] = $q->fields;
    $q->MoveNext();
}

// now let's output it
foreach($items as $item) {
    echo '<p><a href="index.php?main_page=product_info&products_id='. $item['products_id'] .'"><img src="images/'. $item['products_image'].'" alt="'. $item['products_name'].'" title="'. $items['products_name'].'" /></a>';
    echo $items['products_price'] . '</p>';
}
于 2013-07-19T22:10:33.163 回答