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我有一个包含 60-70 个元素的 ArrayList。我为 AutoCompleteTextView 设置了一个适配器，如下所示。

AutoCompleteTextView  mRecipient = (AutoCompleteTextView) this.findViewById(R.id.recipient);
        mRecipient.setThreshold(1);
        Log.i("Array list", ""+names);// Here I got the arrayList
        ArrayAdapter<String> nameadapter=new ArrayAdapter<String>(MyClass.this, android.R.layout.simple_list_item_1, names);
        mRecipient.setAdapter(nameadapter);

但是下拉列表没有显示，我在 Logcat 中收到了一些警告（不是错误）。

04-21 17:15:53.017: W/Filter(15093): An exception occured during performFiltering()!
04-21 17:15:53.017: W/Filter(15093): java.lang.NullPointerException
04-21 17:15:53.017: W/Filter(15093):    at android.widget.ArrayAdapter$ArrayFilter.performFiltering(ArrayAdapter.java:437)
04-21 17:15:53.017: W/Filter(15093):    at android.widget.Filter$RequestHandler.handleMessage(Filter.java:234)
04-21 17:15:53.017: W/Filter(15093):    at android.os.Handler.dispatchMessage(Handler.java:99)
04-21 17:15:53.017: W/Filter(15093):    at android.os.Looper.loop(Looper.java:123)
04-21 17:15:53.017: W/Filter(15093):    at android.os.HandlerThread.run(HandlerThread.java:60)

我在下面还有一个 ListView，现在是空的。

有人能弄清楚这个警告是什么意思吗？

4

1 回答 1

4

警告来自以下代码片段ArrayAdapter.performFiltering(CharSequence)：

 String prefixString = prefix.toString().toLowerCase();  // entered by user
 final ArrayList<T> values = mOriginalValues;
 final int count = values.size();
 final ArrayList<T> newValues = new ArrayList<T>(count); // this will be returned
 for (int i = 0; i < count; i++) {
     final T value = values.get(i);                      // in your case, 'value' is null at times
     final String valueText = value.toString().toLowerCase();  // the warning

     // First match against the whole, non-splitted value
     if (valueText.startsWith(prefixString)) {
         newValues.add(value);
     } else {
         final String[] words = valueText.split(" ");
         final int wordCount = words.length;
         for (int k = 0; k < wordCount; k++) {
             if (words[k].startsWith(prefixString)) {
                 newValues.add(value);
                 break;
             }
         }
     }
 }

因此，请检查null.names

于 2013-07-19T12:44:54.220 回答