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我正在使用 MVC3。以下是我的控制器：

     public ActionResult TRUnutilizedOwnership(string strGeo, string strVertical, int ? intMonth, int ? intFlag) {

         if (strVertical == null) {
             strVertical = "All";
         }
         if (strVertical == "All") {
             intFlag = 1;
         } else {
             intFlag = 2;
         }
         if (intMonth == null) {
             intMonth = 5;
         }
         TRUnutilizedOwnershipModel oTRUnutilizedOwnershipModel = new TRUnutilizedOwnershipModel();
         TravelReadyCommonEntities objTRCommonEntities = new TravelReadyCommonEntities();
         TRUnutilizedOwnershipEntities objTRUnutilizedOwnershipEntities = new TRUnutilizedOwnershipEntities();
         try {
             oTRUnutilizedOwnershipModel.lstGeoEntity = oTRUnutilizedOwnershipModel.GetGeoVertical(strGeo, intFlag);
             if (strGeo == null) {
                 strGeo = oTRUnutilizedOwnershipModel.lstGeoEntity[0].Geo;
             }
             oTRUnutilizedOwnershipModel = oTRUnutilizedOwnershipModel.GetUnutilizedOwnership(strGeo, strVertical, intMonth, intFlag);
             oTRUnutilizedOwnershipModel.lstGeoEntity = oTRUnutilizedOwnershipModel.GetGeoVertical(strGeo, intFlag);
             oTRUnutilizedOwnershipModel.lstVerticalEntity = oTRUnutilizedOwnershipModel.GetGeoVerticalChange(strGeo, 2);
             oTRUnutilizedOwnershipModel.lstMonthEntity = oTRUnutilizedOwnershipModel.GetMonth();
             return View(oTRUnutilizedOwnershipModel);
         } catch (Exception ex) {
             ILogManager LogManager = new LogManager();
             var frame = new StackFrame(0);
             LogManager.CallLogging(frame, ex.Message, ex.StackTrace);
             return RedirectToAction("Error", "Common");
         }
     }

我正在使用以下 jQuery，

function Dispalymaingrid() {
    var Geo = $('#ddlGeo').val();
    var Vertical = $('#ddlVertical').val();
    var Month = $('#ddlMonth').val();
    if (Vertical == "All") {
        var Flag = 1;
    } else {
        var Flag = 2;
    }
    $.ajax({
        url: "@Url.Action("
        TRUnutilizedOwnership ", "
        TravelReady ")",

        datatype: "json",
        type: "post",
        data: {
            strGeo: Geo,
            strVertical: Vertical,
            intMonth: Month,
            intFlag: Flag
        },
        error: function () {},
        success: function (result) {
            debugger;
            //return result;
        }
    });
}

当我从下拉列表中选择某个选项并单击提交按钮时，我的视图页面将显示默认表。必须使用结果值更新表数据。

在 jQuery 的成功功能中我必须提供什么（只有表格内容应该更新）？

4

1 回答 1

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这些信息还不够，但我可以先告诉您应该调试控制器的响应是什么：

$.ajax({
    url: "@Url.Action("
    TRUnutilizedOwnership ", "
    TravelReady ")",

    datatype: "json",
    type: "post",
    data: {
        strGeo: Geo,
        strVertical: Vertical,
        intMonth: Month,
        intFlag: Flag
    },
    error: function (jqXHR, textStatus, errorThrown) {
        console.log(jqXHR);
        console.log(textStatus);
        console.log(errorThrown);
        // display error ?
    },
    success: function (resp) {
        console.log(resp);
        // update the table with resp here, e.g: $('.defaulttable').html(resp) ?
    }
});

明智地使用来自 Firebug 或 Chrome 开发工具的控制台。希望这可以帮助。

于 2013-07-19T10:14:32.630 回答