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我有下表列值：

2013-06-28T13:00:00.000Z    Motion
2013-06-28T18:15:00.000Z    Static  (row2)
2013-07-03T13:57:22.000Z    Moving  (row3)
2013-07-03T13:59:00.000Z    Motion

我想检查日期是否都是静态29-06-2013T01:00:00Z的。同样，我想检查日期和. 如果我们考虑上表的值，显然这是正确的，因为两个日期都在 row2 和 row3 之间。29-06-2013T05:00:00Z30-06-2013T01:00:00Z30-06-2013T05:00:00Z

如何用 sqlite 做到这一点？

我正在获取日期29-06-2013和30-06-2013. 所以首先我需要将时间 1am 和 5am 设置为这两个日期，然后检查它们是否都是Static。

我尝试了以下方法：

Calendar cal1 = Calendar.getInstance();
cal1.setTime(input1.parse(startDate.get(0))); //29-06-2013
cal1.add(Calendar.AM, 1); //Added 1am to date 29-06-2013
weekHours = cal1.getTime(); 

Cursor chkCur1 = dbAdapter.rawQuery("select movement from user where Date <= '"
    + input1.format(weekHours) + "' order by Date asc LIMIT 1", null);

chkCur1.moveToFirst();

if(!chkCur1.isAfterLast() && chkCur1.getString(0).equals("Static"))
{
cal1.add(Calendar.AM, 5); //Added 5am to date 29-06-2013
weekHours = cal1.getTime();
}

chkCur1 = dbAdapter.rawQuery("select movement from user where Date <= '"
    + input1.format(weekHours) + "' order by Date asc LIMIT 1", null);

chkCur1.moveToFirst();

if(!chkCur1.isAfterLast() && chkCur1.getString(0).equals("Static")){
cal1.add(Calendar.DATE, 1);
cal1.add(Calendar.AM, 1); //Added 1am to date 30-06-2013
weekHours = cal1.getTime();


}

chkCur1 = dbAdapter.rawQuery("select movement from user where Date <= '"
    + input1.format(weekHours) + "' order by Date asc LIMIT 1", null);

chkCur1.moveToFirst();

if(!chkCur1.isAfterLast() && chkCur1.getString(0).equals("Static")){
cal1.add(Calendar.AM, 5); //Added 5am to date 30-06-2013
weekHours = cal1.getTime();

}

chkCur1 = dbAdapter.rawQuery("select movement from user where Date <= '"
    + input1.format(weekHours) + "' order by Date asc LIMIT 1", null);

chkCur1.moveToFirst();

if(!chkCur1.isAfterLast() && chkCur1.getString(0).equals("Static")){
System.out.println("Both dates are in between")
}

我使用了 4 个 sql 查询：

1）将时间设置1am为 date1 并检查其先前是否为静态。

2)将时间设置5am为 date1 并检查其前一个是否为静态。

3)将时间设置1am为 date2 并检查其前一个是否为静态。

4)将时间设置5am为 date2 并检查其前一个是否为静态。

如果所有条件都满足，那么两个日期（date1 和 date2）都介于两者之间，即静态。

但这是 sql 查询的重复，从而减慢了进程。

4

1 回答 1

1

您可以将所有四个检查放入子查询中：

SELECT (SELECT movement FROM user WHERE Date <= ? ORDER BY Date) = 'Static'
   AND (SELECT movement FROM user WHERE Date <= ? ORDER BY Date) = 'Static'
   AND (SELECT movement FROM user WHERE Date <= ? ORDER BY Date) = 'Static'
   AND (SELECT movement FROM user WHERE Date <= ? ORDER BY Date) = 'Static';

这将为您提供带有单个布尔列的单个结果记录。

于 2013-07-19T10:06:42.543 回答