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我正在尝试完成上述功能，但收效甚微。我正在使用具有 2 列和 2 行的 GridLayout 向用户展示一个类似拼图的游戏，其中有 4 个（200x200 像素）JPanels（3 个彩色，1 个默认 bgColor）填充了整个 contentPane。如果面板位于灰色面板旁边，则单击彩色面板会在评估中解决。如果是这样，他们应该交换。我已经完成了他们交换的最后一步的每一步。这是代码：

public class MainClass extends JFrame {
//Generated
private static final long serialVersionUID = 4710628273679698058L;

private SpecialPanel redPanel;
private SpecialPanel greenPanel;
private SpecialPanel yellowPanel;
private SpecialPanel grayPanel;

public MainClass() {
    super("Puzzle");

    initPanels();

    setSize(410, 410);
    setLayout(new GridLayout(2, 2));

    this.add(redPanel);
    this.add(greenPanel);
    this.add(grayPanel);
    this.add(yellowPanel);
}
private void initPanels() {
    redPanel = new SpecialPanel();
    greenPanel = new SpecialPanel();
    yellowPanel = new SpecialPanel();
    grayPanel = new SpecialPanel();

    grayPanel.setGreyPanel(true);

    redPanel.setBackground(Color.RED);
    greenPanel.setBackground(Color.GREEN);
    yellowPanel.setBackground(Color.YELLOW);
    grayPanel.setBackground(this.getBackground());

    redPanel.setSize(200, 200);
    greenPanel.setSize(200, 200);
    yellowPanel.setSize(200, 200);
    grayPanel.setSize(200, 200);

    MouseAdapter ma = new MouseAdapter() {

        @Override
        public void mouseClicked(MouseEvent arg0) {
            super.mouseClicked(arg0);

            SpecialPanel sp = (SpecialPanel) arg0.getComponent();

            if (sp.getIsGray()) {
                //Do nothing
            } else if (checkIfNeighbourToGray(sp, grayPanel)) {
                //Swap them
                System.out.println("Swap notification");
                swap(sp, grayPanel);                
                //Update UI
            } else {
                //Again, do nothing for the clicked panel is diagonal to the gray panel
            }
        }

        private boolean checkIfNeighbourToGray(SpecialPanel sp, SpecialPanel grayPanel) {

            Point startPointSp = sp.getLocation();
            double x = startPointSp.getX();
            double y = startPointSp.getY();

            double width = sp.getWidth();
            double height = sp.getHeight();

            Point grayPoint = grayPanel.getLocation();
            double xG = grayPanel.getX();
            double yG = grayPanel.getY();

            double widthG = grayPanel.getWidth();
            double heightG = grayPanel.getHeight();

            //Gray panel is RIGHT of clicked one
            if (x + width == xG && y + height == yG + heightG) {
                return true;                    
            }
            //Gray panel is LEFT of clicked one
            else if (x - width == xG && y + height == yG + heightG) {
                return true;
            }
            //Gray panel is ABOVE of clicked one
            else if (x == xG && x + width == xG + widthG) {
                return true;
            }
            //Gray panel is UNDER of clicked one
            else if (xG == x && yG + widthG == x + width) {
                return true;
            }

            return false;
        }

        private void swap(SpecialPanel sp, SpecialPanel grayPanel) {
            //Swap logic
        }

    };
    redPanel.addMouseListener(ma);
    greenPanel.addMouseListener(ma);
    yellowPanel.addMouseListener(ma);
    grayPanel.addMouseListener(ma);

}
public static void main(String[] args) {
    MainClass mc = new MainClass();
    mc.setVisible(true);

}

}

类 SpecialPanel 正在扩展 JPanel，只是一个新的布尔属性 IsGrayPanel 最初设置为 false + getter 和 setter。注意：这是以“我有基本的 Swing 技能”的方式完成的，虽然我在此期间学到了更多关于 java swing 的知识，但当时我只是受限于基本的 swing 功能，所以我应该保持这种方式。因此我的问题是如何正确交换彼此相邻的两个面板，包括 UI 更新？

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2 回答 2

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  • 不需要将 with 移动JPanels到容器中，否则您需要使用一堆非常无用的代码JPanels从 contianer 中删除两个 with 两个indexes然后布局回容器 with swaping indexes，

  • （如果Color只是）仅在setBackground(Color.Xxx)两个之间交换JPanels

  • puzzle-like game是关于Images，拼图或扫雷艇是关于，（从你的...不清楚）

    1. Images用betweens代替and on切换 ( ) ，加载到Icon/ImageIcons局部变量 JLabelJPanelMouse EventssetIcon()IconsJLabelsIcons

    2. （最简单的方法）JToggleButton 和 Icon，与 for 有类似的逻辑JLabel，但关于Icon显示setPressedIcon()

于 2013-07-18T16:40:51.027 回答
1

我不确定这是否有效。看起来太容易了。

JPanel tempPanel = sp;
sp = grayPanel;
grayPanel = tempPanel;

this.setVisible(false);
this.setVisible(true);
this.validate(); //try this first
this.repaint(); // if it doesnt work, add this function.
于 2013-07-18T16:13:04.320 回答