3

我的表单类型有一个集合字段:

$builder->add('affiliates', 'collection', array(
    'type' => new AffiliateFormType(),
    'allow_add' => true, 
    'allow_delete' => true, 
    'by_reference' => false,
));

在模板中我有:

<table id="affiliates" >
    <tr>
        <th class="t1c0"></th>
        <th class="t1c1" data-prototype="{{ form_widget(form.affiliates.vars.prototype.affiliate_name)|e }}">Name</th>
        <th class="t1c2" data-prototype="{{ form_widget(form.affiliates.vars.prototype.affiliate_type_code)|e }}">Type</th>
        <th class="t1c3" data-prototype="{{ form_widget(form.affiliates.vars.prototype.address)|e }}">Address</th>
    </tr>
    {% for affiliate in form.affiliates %}
    <tr>
        <td class="t1c0"><input type="button" class="delete_button" value="Delete"/></td>
        <td class="t1c1">{{ form_widget(affiliate.affiliate_name) }}{{ form_errors(affiliate.affiliate_name) }}</td>
        <td class="t1c2">{{ form_widget(affiliate.affiliate_type_code) }}{{ form_errors(affiliate.affiliate_type_code) }}</td>
        <td class="t1c3">{{ form_widget(affiliate.address) }}{{ form_errors(affiliate.address) }}</td>
    </tr>
    {% endfor %}
</table>
<input type="button" class="add_button" value="Add line" onclick="addAffiliate();"/>

现在用于添加/删除行的 javasript 代码(带有 jquery)是:

<script language="javascript">

    var affiliatesCollection = $('table#affiliates');

    $(document).ready(function(){
        var rowCount = $('table#affiliates tr').length;
        affiliatesCollection.data('index', rowCount - 1);

        $('.delete_button').click(function(e) {
            $(this).closest("tr").remove();
        });
    });

    function addAffiliate() {
        //get index
        var index = affiliatesCollection.data('index');
        affiliatesCollection.data('index', index + 1);

        //add row
        var cells = new Array();
        var cell = $('<input type="button" class="delete_button" value="Delete"/>').click(function (){
            $(this).closest("tr").remove();
        });
        var $cell = $('<td></td>').append(cell);
        cells[0] = $cell;

        for (var i = 1; i < 4; i++)
        { 
            var prototype = $('th.t1c'.concat(i)).data('prototype');
            var cell = prototype.replace(/__name__/g, index);
            var $cell = $('<td></td>').append(cell);
            cells[i] = $cell;
        }
        var $newRow = $('<tr></tr>').append(cells);
        affiliatesCollection.append($newRow);
    }

</script>

假设名称是必填字段。上面的代码工作正常,除了一种情况:当一行被添加和删除并再次添加时,删除的索引不再可用,如第一行的索引=1,第二行的索引=3;并且当提交无效表单时(例如名称字段为空),form.isValid() 正确返回 false,但验证错误不会显示在其各自元素下方。有人可以帮我纠正这个问题吗?谢谢你。

4

1 回答 1

1

看看 Bernhard Schussek 在这里的评论:

如何将违规添加到集合中?

您必须为集合显式设置error_bubblingfalse(默认为true),以防止错误在树中冒泡到您的主窗体中并在那里显示为全局错误。

正如您(据我在您的问题中看到的)没有{% form_errors(form) %}在您的模板中显示这些全局表单错误,但您的集合的错误现在应该在您的表单中显示为全局错误。

于 2013-07-18T12:56:51.917 回答