13

我正在尝试在我的应用程序中编写一个部分，以区分活动 Wifi 连接和与互联网的实际连接。使用连接管理器确定是否有活动的 Wifi 连接非常简单，但是每次我尝试测试在连接 Wifi 但没有互联网连接时是否可以连接到网站时，我都会陷入无限循环。
我试图 ping 谷歌，但是结果是一样的：

Process p1 = java.lang.Runtime.getRuntime().exec("ping -c 1 www.google.com");
int returnVal = 5;
try {
    returnVal = p1.waitFor();
} catch (InterruptedException e) {
    e.printStackTrace();
}
boolean reachable = (returnVal==0);
return reachable;

我也试过这段代码：

if (InetAddress.getByName("www.xy.com").isReachable(timeout))
{    }
else
{    }

但我无法让 isReachable 工作。

4

7 回答 7

27

它对我有用：

要验证网络可用性：

private Boolean isNetworkAvailable() {
    ConnectivityManager connectivityManager 
          = (ConnectivityManager) getSystemService(Context.CONNECTIVITY_SERVICE);
    NetworkInfo activeNetworkInfo = connectivityManager.getActiveNetworkInfo();
    return activeNetworkInfo != null && activeNetworkInfo.isConnectedOrConnecting();
}

要验证互联网访问：

public Boolean isOnline() {
    try {
        Process p1 = java.lang.Runtime.getRuntime().exec("ping -c 1 www.google.com");
        int returnVal = p1.waitFor();
        boolean reachable = (returnVal==0);
        return reachable;
    } catch (Exception e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }
    return false;
}
于 2014-03-07T17:07:26.607 回答
10

我用这个：

public static void isNetworkAvailable(Context context){
    HttpGet httpGet = new HttpGet("http://www.google.com");
    HttpParams httpParameters = new BasicHttpParams();
    // Set the timeout in milliseconds until a connection is established.
    // The default value is zero, that means the timeout is not used.
    int timeoutConnection = 3000;
    HttpConnectionParams.setConnectionTimeout(httpParameters, timeoutConnection);
    // Set the default socket timeout (SO_TIMEOUT)
    // in milliseconds which is the timeout for waiting for data.
    int timeoutSocket = 5000;
    HttpConnectionParams.setSoTimeout(httpParameters, timeoutSocket);

    DefaultHttpClient httpClient = new DefaultHttpClient(httpParameters);
    try{
        Log.d(TAG, "Checking network connection...");
        httpClient.execute(httpGet);
        Log.d(TAG, "Connection OK");
        return;
    }
    catch(ClientProtocolException e){
        e.printStackTrace();
    }
    catch(IOException e){
        e.printStackTrace();
    }

    Log.d(TAG, "Connection unavailable");
}

它来自另一个 stackoverflow 答案，但我找不到。

编辑：

最后我找到了：https ://stackoverflow.com/a/1565243/2198638

于 2013-07-18T08:20:54.947 回答
4

要检查 android 设备是否有活动连接，我使用下面的 hasActiveInternetConnection() 方法（1）尝试检测网络是否可用，（2）然后连接到 google.com 以确定网络是否处于活动状态。

public static boolean hasActiveInternetConnection(Context context) {
    if (isNetworkAvailable(context)) {
        if (connectGoogle()) {
            return true;
        } else { //one more try
            return connectGoogle();
        }   
    } else {
        log("No network available! (in hasActiveInternetConnection())");
        return false;
    }
}


public static boolean isNetworkAvailable(Context ct) {
    ConnectivityManager connectivityManager = (ConnectivityManager) ct.getSystemService(Context.CONNECTIVITY_SERVICE);
    NetworkInfo activeNetworkInfo = connectivityManager.getActiveNetworkInfo();
    return activeNetworkInfo != null;
}


public static boolean connectGoogle() {
    try {
        HttpURLConnection urlc = (HttpURLConnection)(new URL("http://www.google.com").openConnection());
        urlc.setRequestProperty("User-Agent", "Test");
        urlc.setRequestProperty("Connection", "close");
        urlc.setConnectTimeout(10000); 
        urlc.connect();
        return (urlc.getResponseCode() == 200);     
    } catch (IOException e) {
        log("IOException in connectGoogle())");
        return false;
    }
}
于 2015-03-17T06:56:20.633 回答
4

这是一些现代代码，它使用AsynTask来解决当您尝试在主线程上连接时 android 崩溃的问题，并为用户引入带有冲洗和重复选项的警报。

class TestInternet extends AsyncTask<Void, Void, Boolean> {
    @Override
    protected Boolean doInBackground(Void... params) {
        try {
            URL url = new URL("http://www.google.com");
            HttpURLConnection urlc = (HttpURLConnection) url.openConnection();
            urlc.setConnectTimeout(3000);
            urlc.connect();
            if (urlc.getResponseCode() == 200) {
                return true;
            }
        } catch (MalformedURLException e1) {
            // TODO Auto-generated catch block
            e1.printStackTrace();
            return false;
        } catch (IOException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
            return false;
        }
        return false;
    }

    @Override
    protected void onPostExecute(Boolean result) {
        if (!result) { // code if not connected
            AlertDialog.Builder builder = new AlertDialog.Builder(MainActivity.this);
            builder.setMessage("An internet connection is required.");
            builder.setCancelable(false);

            builder.setPositiveButton(
                    "TRY AGAIN",
                    new DialogInterface.OnClickListener() {
                        public void onClick(DialogInterface dialog, int id) {
                            dialog.cancel();
                            new TestInternet().execute();
                        }
                    });


            AlertDialog alert11 = builder.create();
            alert11.show();
        } else { // code if connected
            doMyStuff();
        }
    }
}

...

new TestInternet().execute();
于 2016-11-13T17:36:51.740 回答
2

像这样查询一个网站：

通过向您的类AsyncTaskCompleteListenere<Boolean>添加以下方法来实现您的类：

@Override
public void onTaskComplete(Boolean result) {
    Toast.makeText(getApplicationContext(), "URL Exist:" + result, Toast.LENGTH_LONG).show();
   // continue your job
}

testConnection当您想要检查连接性时，向您的类添加一个要调用的简单方法：

public void testConnection() {
        URLExistAsyncTask task = new URLExistAsyncTask(this);
        String URL = "http://www.google.com";
        task.execute(new String[]{URL});
    }

最后，URLExistAsyncTask将连接测试作为异步（后台）任务执行并onTaskComplete在完成后回调您的方法的类：

  public class URLExistAsyncTask extends AsyncTask<String, Void, Boolean> {
        AsyncTaskCompleteListenere<Boolean> callback;

        public URLExistAsyncTask(AsyncTaskCompleteListenere<Boolean> callback) {
            this.callback = callback;
        }

        protected Boolean doInBackground(String... params) {
            int code = 0;
            try {
                URL u = new URL(params[0]);
                HttpURLConnection huc = (HttpURLConnection) u.openConnection();
                huc.setRequestMethod("GET");
                huc.connect();
                code = huc.getResponseCode();
            } catch (IOException e) {
                return false;
            } catch (Exception e) {
                return false;
            }

            return code == 200;
        }

        protected void onPostExecute(Boolean result){
              callback.onTaskComplete(result);
        }
    }
于 2013-07-18T08:20:56.777 回答
2

我确实使用了这种方法。它对我有用！对于想要获得真正互联网的人！

public boolean isOnline() {
    try {
        HttpURLConnection httpURLConnection = (HttpURLConnection)(new URL("http://www.google.com").openConnection());
        httpURLConnection.setRequestProperty("User-Agent", "Test");
        httpURLConnection.setRequestProperty("Connection", "close");
        httpURLConnection.setConnectTimeout(10000);
        httpURLConnection.connect();
        return (httpURLConnection.getResponseCode() == 200);
    } catch (IOException e) {
        e.printStackTrace();
        return false;
    }
}

每次都做这个方法！只需使用接收器和=>

httpURLConnection.getResponseCode() == 200

这意味着互联网已连接！

于 2017-05-07T09:23:03.470 回答
0

您可以通过创建new parallel thread该计数时间来做到这一点：

final class QueryClass {
    private int responseCode = -1;
     private   String makeHttpRequest(URL url) throws IOException {
            String jsonResponse = "";
            if(url == null) {
                return null;
            }

            HttpURLConnection  urlConnection = null;
            InputStream inputStream = null;
            try {
                urlConnection = (HttpURLConnection) url.openConnection();
                urlConnection.setRequestMethod("GET");
                urlConnection.setReadTimeout(5000 );
                urlConnection.setConnectTimeout(5000 );
                Thread thread = new Thread() {
                    @Override
                    public void run() {
                        super.run();
                        try {
                            sleep(5000);
                        } catch (InterruptedException e) {
                            e.printStackTrace();
                        }
                        if(responseCode == -1) {
                            //Perform error message
                        Intent intent = new Intent(context,ErrorsActivity.class);
                        intent.putExtra("errorTextMessage",R.string.errorNoInternet);
                        intent.putExtra("errorImage",R.drawable.no_wifi);
                        context.startActivity(intent);
                        }
                    }
                };
                thread.start();
                urlConnection.connect();
                 responseCode = urlConnection.getResponseCode();
                if (responseCode == 200) {
                    inputStream = urlConnection.getInputStream();
                    jsonResponse = readFromStream(inputStream);

                }
于 2019-05-16T07:27:31.663 回答