我做了一些你最近要求的东西（使用 T4 模板），所以这是绝对可能的：
https://github.com/xaviergonz/T4Immutable
例如，鉴于此：
[ImmutableClass(Options = ImmutableClassOptions.IncludeOperatorEquals)]
class Person {
private const int AgeDefaultValue = 18;
public string FirstName { get; }
public string LastName { get; }
public int Age { get; }
[ComputedProperty]
public string FullName {
get {
return FirstName + " " + LastName;
}
}
}
它会在一个单独的部分类文件中自动为您生成以下内容：
- 将初始化值的构造函数，例如 public Person(string firstName, string lastName, int age = 18)。
- Equals(object other) 和 Equals(Person other) 的工作实现。它还将为您添加 IEquatable 接口。operator== 和 operator!= 的工作实现
- GetHashCode() 的工作实现 更好的 ToString() 输出，例如“Person { FirstName=John, LastName=Doe, Age=21 }”
- 一种 Person With(...) 方法，可用于生成具有 0 个或多个属性更改的新不可变克隆（例如 var janeDoe = johnDoe.With(firstName: "Jane", age: 20)
所以它会生成这个（不包括一些冗余属性）：
using System;
partial class Person : IEquatable<Person> {
public Person(string firstName, string lastName, int age = 18) {
this.FirstName = firstName;
this.LastName = lastName;
this.Age = age;
_ImmutableHashCode = new { this.FirstName, this.LastName, this.Age }.GetHashCode();
}
private bool ImmutableEquals(Person obj) {
if (ReferenceEquals(this, obj)) return true;
if (ReferenceEquals(obj, null)) return false;
return T4Immutable.Helpers.AreEqual(this.FirstName, obj.FirstName) && T4Immutable.Helpers.AreEqual(this.LastName, obj.LastName) && T4Immutable.Helpers.AreEqual(this.Age, obj.Age);
}
public override bool Equals(object obj) {
return ImmutableEquals(obj as Person);
}
public bool Equals(Person obj) {
return ImmutableEquals(obj);
}
public static bool operator ==(Person a, Person b) {
return T4Immutable.Helpers.AreEqual(a, b);
}
public static bool operator !=(Person a, Person b) {
return !T4Immutable.Helpers.AreEqual(a, b);
}
private readonly int _ImmutableHashCode;
private int ImmutableGetHashCode() {
return _ImmutableHashCode;
}
public override int GetHashCode() {
return ImmutableGetHashCode();
}
private string ImmutableToString() {
var sb = new System.Text.StringBuilder();
sb.Append(nameof(Person) + " { ");
var values = new string[] {
nameof(this.FirstName) + "=" + T4Immutable.Helpers.ToString(this.FirstName),
nameof(this.LastName) + "=" + T4Immutable.Helpers.ToString(this.LastName),
nameof(this.Age) + "=" + T4Immutable.Helpers.ToString(this.Age),
};
sb.Append(string.Join(", ", values) + " }");
return sb.ToString();
}
public override string ToString() {
return ImmutableToString();
}
private Person ImmutableWith(T4Immutable.WithParam<string> firstName = default(T4Immutable.WithParam<string>), T4Immutable.WithParam<string> lastName = default(T4Immutable.WithParam<string>), T4Immutable.WithParam<int> age = default(T4Immutable.WithParam<int>)) {
return new Person(
!firstName.HasValue ? this.FirstName : firstName.Value,
!lastName.HasValue ? this.LastName : lastName.Value,
!age.HasValue ? this.Age : age.Value
);
}
public Person With(T4Immutable.WithParam<string> firstName = default(T4Immutable.WithParam<string>), T4Immutable.WithParam<string> lastName = default(T4Immutable.WithParam<string>), T4Immutable.WithParam<int> age = default(T4Immutable.WithParam<int>)) {
return ImmutableWith(firstName, lastName, age);
}
}
如项目页面中所述，还有更多功能。
PS：如果您想要一个包含其他不可变对象列表的属性，只需添加：
public ImmutableList<string> Jobs { get; }