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我有一个辅助表

时间 分钟
2013-01-01 09:00:00.000 1
2013-01-01 09:01:00.000 1
2013-01-01 09:02:00.000 1
2013-01-01 09:03:00.000 1
2013-01- 01 09:04:00.000 1
2013-01-01 09:05:00.000 1

（时间范围是 09 到 17 之间的每一天）。

下表如下所示

ID OPEN_TIME TITLE SLA
1 2012-12-17 11:46:47.000 AAA
2 2012-12-18 09:33:18.000 BBB
3 2012-12-18 13:14:02.000 CCC
4 2012-12-19 14:23: 53.000 DDD
5 2013-01-03 07:48:11.000 EEE

如何在“当前时间（systime）”和“OPEN_TIME”之间的时间间隔/范围内计算第一个表的分钟数？
+ 结果（计数/分钟总和）应在之后为每条记录添加到 SLA 列中。

有没有可能的解决方案？（SQL 服务器）

谢谢！

4

3 回答 3

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例如，在SQL Server中 datediff 将完成您的工作

SELECT datediff(mi,'2012-12-17 11:46:47.000' , '2012-12-17 11:47:47.000')

这将显示 1，因为两个间隔之间存在微小差异。

于 2013-07-17T13:14:47.313 回答
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您必须使用以下功能来获得微小的差异。

SELECT TIMESTAMPDIFF(MINUTE,opentime,endtime);

请参考

http://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html#function_timestampdiff

于 2013-07-17T11:38:22.517 回答
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我假设您需要一个函数来增加升级时间的分钟数，但仅限于工作时间。

你可以通过使用类似的东西从你的第一张桌子计算你的分钟数

Select SUM(Minute) from auxiliary  where Time <= CURRENT_TIMESTAMP

以下函数将执行此操作，跳过@SCStartHours 和@SCEndHours 之外的任何时间。周六和周日之外：

该函数将像这样使用：

将 60 个“工作分钟”添加到 OPEN_TIME：

select AddWorkingMinutes(OPEN_TIME, 60, 9,17)


    create Function AddWorkingMinutes(@EscalateOnDate datetime, @escalationminutes int, 

@SCStartHours int, @SCEndHours int)
returns datetime
as
begin

declare @workminutesperday int = (@SCEndHours - @SCStartHours)*60
declare @workdays int = @escalationminutes/@workminutesperday
declare @minutes int = @escalationminutes - @workminutesperday * @workdays


-- If the date falls out of hours then move it forward to the next earliest period
while DATENAME(weekday, @EscalateOnDate ) = 'Saturday' 
      OR DATENAME(weekday, @EscalateOnDate ) = 'Sunday'
      OR DATEPART(hour, @EscalateOnDate ) >= @SCEndHours
begin
set @EscalateOnDate = DATEADD(dd,1,@EscalateOnDate )
set @EscalateOnDate = DATEADD(hh,@SCStartHours,DATEADD(dd,0, DATEDIFF(dd,0, @EscalateOnDate )))
end
while  DATEPART(hour,@EscalateOnDate ) < @SCStartHours
begin
set @EscalateOnDate = DATEADD(hh,@SCStartHours,DATEADD(dd,0, DATEDIFF(dd,0, @EscalateOnDate )))
end

--now check if we have enough minutes in the day remaining, if not add a day and take the remaining minutes off.
declare @minutesremaining int = DATEDIFF(minute, @EscalateOnDate , DATEADD(hh,@SCEndHours,DATEADD(dd,0, DATEDIFF(dd,0, @EscalateOnDate ))))
if @minutesremaining < @minutes
begin
set @minutes = @minutes - @minutesremaining
set @workdays = @workdays + 1
set @EscalateOnDate = DATEADD(hh,@SCStartHours,DATEADD(dd,0, DATEDIFF(dd,0, @EscalateOnDate )))
end

return DATEADD(minute,@minutes,DATEADD(day, (@workdays % 5) + CASE ((@@DATEFIRST + DATEPART(weekday, @EscalateOnDate ) + (@workdays % 5)) % 7)
                                                 WHEN 0 THEN 2
                                                 WHEN 1 THEN 1
                                                 ELSE 0 END, DATEADD(week, (@workdays / 5), @EscalateOnDate )))
end
于 2013-07-17T13:31:00.420 回答