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我正在玩 D3 并制作力有向图。我想清除并重新加载图表以响应单击按钮。但是，当我重新加载已加载的图表时，该图表的格式不正确。这是我正在使用的代码：

<!DOCTYPE html>
<meta charset="utf-8">
<script src="http://d3js.org/d3.v2.js?2.9.1"></script>
<style>

.link {
  fill: none;
  stroke: #666;
  stroke-width: 1.5px;
}

.node circle {
  fill: #ccc;
  stroke: #fff;
  stroke-width: 1.5px;
}

text {
  font: 10px sans-serif;
  pointer-events: none;
}

</style>
<body>
<script>

var all = [
{source: "Tockwotton", target: "List", type: "woodworking"},
{source: "Tockwotton", target: "Prince Lab", type: "woodworking"},
{source: "Prince Lab", target: "Prince Lab", type: "metalworking"},
{source: "Tockwotton", target: "List", type: "cnc"},
{source: "Granoff", target: "Prince Lab", type: "3d-printing"},
{source: "Tockwotton", target: "List", type: "drafting"},
{source: "List", target: "Prince Lab", type: "welding"},
{source: "Prince Lab", target: "Prince Lab", type: "sand-blaster"},
{source: "Tockwotton", target: "List", type: "finishing"},
{source: "Tockwotton", target: "Prince Lab", type: "finishing"},
{source: "Tockwotton", target: "Tockwotton", type: "laser-cutter"}
];

var wood = [
{source: "Tockwotton", target: "List", type: "woodworking"},
{source: "Tockwotton", target: "Prince Lab", type: "woodworking"}
];

var metal = [
{source: "Prince Lab", target: "Prince Lab", type: "metalworking"}
];

var cnc = [
{source: "Tockwotton", target: "List", type: "cnc"}
];

var print = [
{source: "Granoff", target: "Prince Lab", type: "3d-printing"}
];

var draft = [
{source: "Tockwotton", target: "List", type: "drafting"}
];

var weld = [
{source: "List", target: "Prince Lab", type: "welding"}
];

var sand = [
{source: "Prince Lab", target: "Prince Lab", type: "sand-blaster"}
];

var finishing = [
{source: "Tockwotton", target: "List", type: "finishing"},
{source: "Tockwotton", target: "Prince Lab", type: "finishing"}
];

var laser = [
{source: "Tockwotton", target: "Tockwotton", type: "laser-cutter"}
];

function render(linkdata){  

d3.selectAll("svg").remove();

links = linkdata;

nodes = {};

// Compute the distinct nodes from the links.
links.forEach(function(link) {
  link.source = nodes[link.source] || (nodes[link.source] = {name: link.source, type: link.type});
  link.target = nodes[link.target] || (nodes[link.target] = {name: link.target, type: link.type});
});

width = 960,
    height = 500;

force = d3.layout.force()
    .nodes(d3.values(nodes))
    .links(links)
    .size([width, height])
    .linkDistance(60)
    .charge(-300)
    .on("tick", tick)
    .start();

svg = d3.select("body").append("svg")
    .attr("width", width)
    .attr("height", height);

link = svg.selectAll(".link")

    .data(force.links())
    .enter().append("line")
    .attr("class", "link");

node = svg.selectAll(".node")
    .data(force.nodes())
  .enter().append("g")
    .attr("class", "node")
    .on("mouseover", mouseover)
    .on("mouseout", mouseout)
    .call(force.drag);

node.append("circle")
    .attr("r", 8);

node.append("text")
    .attr("x", 12)
    .attr("dy", ".35em")
    .text(function(d) { return d.name; });

function tick() {
  link
      .attr("x1", function(d) { return d.source.x; })
      .attr("y1", function(d) { return d.source.y; })
      .attr("x2", function(d) { return d.target.x; })
      .attr("y2", function(d) { return d.target.y; });

  node
      .attr("transform", function(d) { return "translate(" + d.x + "," + d.y + ")"; });
}

function mouseover() {
  d3.select(this).select("circle").transition()
      .duration(750)
      .attr("r", 16);
}

function mouseout() {
  d3.select(this).select("circle").transition()
      .duration(750)
      .attr("r", 8);
}
}
</script>

<div id="nav">
    <div id="wood">
        <a onclick="render(wood)">Woodworking</a>
    </div>
    <div id="metal">
        <a onclick="render(metal)">Metalworking</a>
    </div>
    <div id="cnc">
        <a onclick="render(cnc)">CNC</a>
    </div>
    <div id="print">
        <a onclick="render(print)">3D Printing</a>
    </div>
    <div id="draft">
        <a onclick="render(draft)">Drafting</a>
    </div>
    <div id="weld">
        <a onclick="render(weld)">Welding</a>
    </div>
    <div id="sand">
        <a onclick="render(sand)">Sand Blast</a>
    </div>
    <div id="finishing">
        <a onclick="render(finishing)">Finishing</a>
    </div>
    <div id="laser">
        <a onclick="render(laser)">Laser Cutting</a>
    </div>
    <div id="all">
        <a onclick="render(all)">All</a>
    </div>
</div>

</body>

尝试一下，注意第一次单击一个项目时，它工作正常，但如果再次单击它，你只会得到一个名为[object Object]. 为什么会这样，我该如何解决？

4

1 回答 1

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当您使用links = linkdata时，它可能没有按照您的预期进行。像其他一些语言一样，这不会复制数据；相反，它只是links指向指向的同一个地方linkdata。当您遍历links，将它们修改为指向彼此时，您正在修改数组中的原始对象。当您再次遍历它们时，它们已经被修改，导致您遇到不良行为。

为避免这种命运，您需要在修改数组之前对其进行深度复制。有很多方法可以做到这一点，但您需要确保您使用的任何解决方案都可以将数组克隆为数组，而不会将其转换为普通数组Object。

于 2013-07-17T04:37:43.560 回答