我认为你想要你的价值观的所有组合....
这是在 C# 中执行此操作的通用方法...
static IEnumerable<IEnumerable<T>> Combinations<T>(IEnumerable<T> list, int length)
{
if (length == 1) return list.Select(t => new T[] { t });
return Combinations(list, length - 1)
.SelectMany(t => list, (t1, t2) => t1.Concat(new T[] { t2 }));
}
你这样称呼它...
var groups = new List<string>() { "R1", "R2", "R3" };
var values = new List<string>() { "AA", "AB", "BB" };
var combinations = Combinations(values, groups.Count);
var i = 0;
var stringFormat = string.Join(", ", groups.Select(x => x +"={"+ i++ +"}"));
// stringFormat looks like "R1={0}, R2={1}, R3={2}"
foreach (var value in combinations)
{
var arrayOfValues = value.ToArray(); // each value is a list of the combinations.
Console.WriteLine(string.Format(stringFormat, arrayOfValues));
}
你提到你的经验不足,所以我已经包括了用更容易理解的硬编码方式来做这件事......
var values = new List<string>() { "AA", "AB", "BB" };
foreach (var value1 in values)
{
foreach (var value2 in values)
{
foreach (var value3 in values)
{
Console.WriteLine(string.Format("R1 = {0}, R2 = {1}, R3 = {2}", value1, value2, value3));
}
}
}
输出看起来像这样......
R1=AA, R2=AA, R3=AA
R1=AA, R2=AA, R3=AB
R1=AA, R2=AA, R3=BB
R1=AA, R2=AB, R3=AA
R1=AA, R2=AB, R3=AB
R1=AA, R2=AB, R3=BB
R1=AA, R2=BB, R3=AA
R1=AA, R2=BB, R3=AB
R1=AA, R2=BB, R3=BB
R1=AB, R2=AA, R3=AA
R1=AB, R2=AA, R3=AB
R1=AB, R2=AA, R3=BB
R1=AB, R2=AB, R3=AA
R1=AB, R2=AB, R3=AB
R1=AB, R2=AB, R3=BB
R1=AB, R2=BB, R3=AA
R1=AB, R2=BB, R3=AB
R1=AB, R2=BB, R3=BB
R1=BB, R2=AA, R3=AA
R1=BB, R2=AA, R3=AB
R1=BB, R2=AA, R3=BB
R1=BB, R2=AB, R3=AA
R1=BB, R2=AB, R3=AB
R1=BB, R2=AB, R3=BB
R1=BB, R2=BB, R3=AA
R1=BB, R2=BB, R3=AB
R1=BB, R2=BB, R3=BB