我正在尝试复制某些网格视口的行为（例如3ds Max的正交视图）
或地图查看器（如GoogleMaps）的行为，其中我们有地图或网格，它
比屏幕大得多，我们导航单击视口中的某处并拖动。
到目前为止，我已经设法创建了一个相当大的网格，绘制它并使视口只显示它应该显示的图块。
到目前为止，这是我的代码：
import pygame, sys, math
from pygame.locals import *
FPS = 30
WINDOWWIDTH = 640
WINDOWHEIGHT = 480
GRIDWIDTH = 256
GRIDHEIGHT = 256
GRIDSIZE = 256
TILESIZE = 40
BGCOLOR = (128, 128, 128)
FGCOLOR = (64, 64, 64)
GRID = []
FPSCLOCK = pygame.time.Clock()
indexX = None
indexY = None
minVPcoordX = 0
minVPcoordY = 0
maxVPcoordX = (TILESIZE*GRIDSIZE)-WINDOWWIDTH
maxVPcoordY = (TILESIZE*GRIDSIZE)-WINDOWHEIGHT
viewportOffset = (0, 0)
vpStartXTile = 0
vpStartYTile = 0
viewportCoord = (0, 0)
coordX = 0
coordY = 0
movedDistanceX = 0
movedDistanceY = 0
speed = 4
def main():
global FPSCLOCK, DISPLAYSURF
global coordX, coordY
global offsetX, offsetY, negativeOffsetX, negativeOffsetY
global movedDistanceX, movedDistanceY
DISPLAYSURF = pygame.display.set_mode((WINDOWWIDTH, WINDOWHEIGHT))
mouseX = 0
mouseY = 0
generateGrid(GRIDSIZE, GRIDSIZE)
LeftButton = False
mousePos = (0, 0)
dragStart = (0,0)
dragEnd = (0,0)
pygame.font.init()
arialFnt = pygame.font.SysFont('Arial', 16)
while True:
DISPLAYSURF.fill(BGCOLOR)
for event in pygame.event.get():
if event.type == QUIT:
pygame.quit()
sys.exit()
#X
if coordX < maxVPcoordX:
coordX += speed
elif coordX < minVPcoordX:
coordX = 0
else:
coordX = maxVPcoordX
#Y
if coordY < maxVPcoordY:
coordY += speed
elif coordY < minVPcoordY:
coordY = 0
else:
coordY = maxVPcoordY
#-------------
viewportCoord = (coordX, coordY)
print(coordX, coordY)
vpStartXTile = math.floor(float(viewportCoord[0]/TILESIZE))
vpStartYTile = math.floor(float(viewportCoord[1]/TILESIZE))
GRIDstartTile = GRID[vpStartXTile][vpStartYTile]
negativeOffsetX = viewportCoord[0] - GRID[vpStartXTile][vpStartYTile][0]
negativeOffsetY = viewportCoord[1] - GRID[vpStartXTile][vpStartYTile][1]
offsetX = TILESIZE - negativeOffsetX
offsetY = TILESIZE - negativeOffsetY
repeatX = math.floor(WINDOWWIDTH/TILESIZE)
repeatY = math.floor(WINDOWHEIGHT/TILESIZE)
drawGrid(repeatX, repeatY)
outputLabel = arialFnt.render('(Top-Left)Coordinates: x%s - y%s' % (coordX, coordY), 1, (255,255,255))
DISPLAYSURF.blit(outputLabel, (10, 10))
# frame draw
pygame.display.set_caption("Memory Game - FPS: %.0f" % FPSCLOCK.get_fps())
pygame.display.flip()
pygame.display.update()
FPSCLOCK.tick(FPS)
def generateGrid(xTiles=None, yTiles=None):
global GRID
GRID = []
for i in range(xTiles):
GRID.append([None] * yTiles)
ix = 0
iy = 0
posX = -40
for x in range(len(GRID[ix])):
posX += TILESIZE
posY = -40
iy = 0
for y in range(xTiles):
posY += TILESIZE
position = (posX, posY)
GRID[ix][iy] = position
iy += 1
if ix < xTiles:
ix += 1
else:
return
def drawGrid(x=None, y=None):
lineWidth = 1
xPos = 0
yPos = 0
for i in range(x):
xStart = (xPos + offsetX, 0)
xEnd = (xPos + offsetX, WINDOWHEIGHT + negativeOffsetY)
pygame.draw.line(DISPLAYSURF, FGCOLOR, xStart, xEnd, lineWidth)
xPos += TILESIZE
for i in range(y):
yStart = (0, yPos + offsetY)
yEnd = (WINDOWWIDTH + negativeOffsetX, yPos + offsetY)
pygame.draw.line(DISPLAYSURF, FGCOLOR, yStart, yEnd, lineWidth)
yPos += TILESIZE
def moveGrid():
pass
def zoomIn():
pass
def zoomOut():
pass
main()
如您所见，它按预期工作（我没有
在此示例中实现任何形式的单击和拖动）。
看来pygame没有这个事件，所以一定是
MOUSEBUTTONDOWN和MOUSEMOTION的组合。
我尝试使用get_pos()存储前一帧的位置并减去当前帧的位置，但我不知道下一帧的位置。它加速得太快了..
我也用get_rel()试过这个方法试过这个，但没有成功。
（虽然我很确定我不应该将鼠标位置 ++ 到屏幕位置）
我四处研究，看看是否有其他人这样做，但我只发现了如何拖动某些东西
我四处研究看看是否有其他人这样做，但我只发现如何在固定屏幕上我需要相反的 - 在固定网格上拖动屏幕。
所以，如果有人对如何制作这个机制有任何想法或建议，或者我可以研究它的任何链接，我将不胜感激！
ps：我发现了类似的东西，但它是用JS编写的，翻译起来很痛苦）