public class MyAction extends Action
{
public ActionForward execute(ActionMapping mapping, ActionForm form,HttpServletRequest request, HttpServletResponse response)throws Exception {
String status="success";
HttpSession session = request.getSession(true);
System.out.println("My Action---setting key value");
request.getSession().setAttribute("key1","check");
//response.sendRedirect("http://localhost:9080/FamiliarPortal/jsp/inicio.jsp");
return mapping.findForward(status);
}
}
在Struts-config.xml
中,添加了以下内容:
<action path="/myAction" type="iusa.ubicacel.actions.MyAction" validate="false" >
<forward name="success" path="/jsp/inicio.jsp"/>
</action>
在web.xml
中,添加了以下内容:
<servlet>
<servlet-name>GetFAP</servlet-name>
<servlet-class>iusa.ubicacel.actions.map.GetFAP</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>action</servlet-name>
<url-pattern>*.do</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>GetFAP</servlet-name>
<url-pattern>/GetFAP</url-pattern>
</servlet-mapping>
在inicio.jsp
中,添加了以下内容:
<BODY onload="requestXML('<%=reqURL %>');">
<table border="0" cellspacing="0" cellpadding="0" align="center">
<tr>
<td align="center" valign="middle">
<div id="mapdiv" style="width: 1000px; height:700px"></div>
</td>
</tr>
</table>
</BODY>
功能requestXML
如下:
function requestXML(reqURL)
{
alert("calling requestXML"+reqURL);
var url = "../GetFAP?requestURL=" + reqURL;
alert("calling requestXML"+url);
xmlhttpUbi = FAPXMLHttpRequest();
xmlhttpUbi.open("POST", url, true); // async
alert("after calling");
xmlhttpUbi.onreadystatechange = obtainFAPLocation;
xmlhttpUbi.send(null);
}
上面的代码在使用mapping.findForward
. 但是当我使用response.sendRedirect("entire jsp path")
它时,它正在调用 servlet。
谁能告诉我我在这里做错了什么?