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如何获取 ListView 的值并在单击时显示该值？

我从 mysql 数据库中获取值。

public class SearchlistviewActivity extends Activity {
    /** Called when the activity is first created. */
    private ListView lv1;

    private ArrayList<String> arr_sort= new ArrayList<String>();
    int textlength=0;
    private ArrayList<String> map= new ArrayList<String>();

    protected int selected;
    //private  ArrayList<HashMap<String, String>> listItem = new ArrayList<HashMap<String>>();

    @SuppressWarnings("unchecked")
    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);

        lv1=(ListView)findViewById(R.id.listView1); 

        getServerData(strURL);

        lv1.setAdapter(new ArrayAdapter<String>(this,android.R.layout.simple_list_item_1 , map));

        lv1.setOnItemClickListener(new OnItemClickListener() {

            public void onItemClick(AdapterView arg0, View v, int position,
             long id) {
                Toast.makeText(SearchlistviewActivity.this,"Listed", Toast.LENGTH_SHORT).show();
            }
        });
    }

    public static final String strURL = "http://192.168.0.2/ville.php";

    private String getServerData(String returnString ) {
        InputStream is = null;
        String result = "";

        ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
        nameValuePairs.add(new BasicNameValuePair("ville",""));

        try {
            HttpClient httpclient = new DefaultHttpClient();
            String http="http://" ;
            String myip ="192.168.0.2" ;
            String vil="/ville.php";
            String myurl=http+myip+vil;

            HttpPost httppost = new HttpPost(myurl);
            httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
            HttpResponse response = httpclient.execute(httppost);
            HttpEntity entity = response.getEntity();
            is = entity.getContent();
        } catch(Exception e) {
            Log.e("log_tag", "Error in http connection " + e.toString());
        }

        try {
            BufferedReader reader = new BufferedReader(new InputStreamReader(is,"iso-8859-1"),8);
            StringBuilder sb = new StringBuilder();
            String line = null;
            while ((line = reader.readLine()) != null) {
                sb.append(line + "\n");
            }
            is.close();
            result=sb.toString();
        } catch(Exception e) {
            Log.e("log_tag", "Error converting result " + e.toString());
        }
        // Parse les donnA©es JSON
        try {
            JSONArray jArray = new JSONArray(result);
            for(int i=0;i<jArray.length();i++){
                JSONObject json_data = jArray.getJSONObject(i);

                Log.i("log_tag","CostumerOrder: "+json_data.getString("CostumerOrder")+
                        ", OrderPrice: "+json_data.getString("OrderPrice")
                );

                map.add(json_data.getString("CostumerOrder").toString());
            }
        } catch(JSONException e) {
            Log.e("log_tag", "Error parsing data " + e.toString());
        }
        return returnString; 
    }
}
4

2 回答 2

0 
lv1.setOnItemClickListener(new OnItemClickListener() {

        public void onItemClick(AdapterView arg0, View v, int position,
         long id) {
            Toast.makeText(SearchlistviewActivity.this,"Listed", Toast.LENGTH_SHORT).show();
        }
        });

}

在 onItemClicke 中，您可以获得被点击项目的位置或索引，您可以通过数组中的索引获取对象，然后您可以在任何地方使用它。

希望这会帮助你。

于 2013-07-16T11:59:06.787 回答
0 
String selectedFromList = (listview.getItemAtPosition(position));
Toast.makeText(context, selectedFromList, Toast.LENGTH_SHORT).show();

在您的列表项中单击

于 2013-07-16T11:57:55.057 回答