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我从 XML 解析中获取日期字符串，如下所示：2012-04-05 07:55:29 +05.30

现在，我希望这个字符串为：05-April-2012

我怎样才能做到这一点？

4

4 回答 4

8

首先解析这个迄今为止。

String time = "Sun Jul 15 2012 12:22:00 GMT+03:00 (FLE Daylight Time)";
SimpleDateFormat sdf = new SimpleDateFormat("EEE MMM dd yyyy HH:mm:ss zzz");
Date date = sdf.parse(time);


SimpleDateFormat sdf=new SimpleDateFormat("dd-MMM-yyyy");
String s=sdf.format(date.getTime());
于 2013-07-16T10:47:23.447 回答
2

您可以单独拆分所有内容，然后按照您的意愿进行格式化；

public String getDateFromString(String dateString){
    if(dateString!=null){
        String[] dateRoot=dateString.split(" ");
        String ymd=dateRoot[0];
        String hms= dateRoot[1];
        String[] calRoot=ymd.split("-");
        int year=Integer.parseInt(calRoot[0]);
        int month=Integer.parseInt(calRoot[1]);
        int day=Integer.parseInt(calRoot[2]);

        String[] timeRoot=hms.split(":");
        int hour=Integer.parseInt(timeRoot[0]);
        int minute=Integer.parseInt(timeRoot[1]);
        int second=Integer.parseInt(timeRoot[2]);

        String newFormat =  day+"-"+month+"-"+year;

        return newFormat;
        }
    return null;
}
于 2013-07-16T10:30:03.860 回答
2

考虑，

String date="2012-04-05 07:55:29 +05.30";
//split the above string based on space
String[] dateArr=date.split(" ");

//Now in dateArr[0] you will have 2012-04-05, split this based on "-" to get yy,mm,dd
String[] yymmdd=dateArr[0].split("-");

//Now in get month name using a String array
String months[12]={"Jan","Feb","Mar","April","May","June","July","Aug","Sept","oct","Nov","Dec"};

//Now index to the above array will be your yymmdd[1]-1 coz array index starts from 0
String yy=yymmdd[0];
String dd=yymmdd[2];
String mm=months[Integer.parseInt(yymmdd[1])-1];

//Now you have the dd,mm,and yy as you need, So you can concatenate and display it

String myDate=dd+"-"+mm+"-"+yy;

//myDate will have the string you need
于 2013-07-16T10:42:57.087 回答
1

用作("dd-MMMMMMMMM-yyyy")DateStringFormat

于 2013-07-16T10:26:46.583 回答