2

我在列表视图中添加一个可绘制图像作为标题。如果有活动，我已按如下方式实施。

listView1 = (ListView)findViewById(R.id.listView1);

    View header = (View)getLayoutInflater().inflate(R.layout.header, null);
    listView1.addHeaderView(header);

但是，现在我正在尝试在这样的 viewpager 片段中实现相同的功能

import android.os.Bundle;
import android.support.v4.app.Fragment;
import android.view.LayoutInflater;
import android.view.View;
import android.view.ViewGroup;
import android.widget.ArrayAdapter;
import android.widget.ListView;

public class ShowFrag1 extends Fragment {
    @Override
    public View onCreateView(LayoutInflater inflater, ViewGroup container, 
        Bundle savedInstanceState) {
        // Inflate the layout for this fragment
        View v=inflater.inflate(R.layout.frag1, container,false);
        ListView lv1=(ListView) v.findViewById(R.id.listView1);

        Level weather_data[] = new Level[]
                {
                    new Level(R.drawable.s1, "L1", R.drawable.p),
                    new Level(R.drawable.s2, "L2",R.drawable.p),
                    new Level(R.drawable.s3, "L3",R.drawable.p),
                    new Level(R.drawable.s4, "L4",R.drawable.p),
                    new Level(R.drawable.s6, "L5",R.drawable.p)
                };
        LevelAdapter adapter = new LevelAdapter(getActivity(),
                R.layout.list_item, weather_data);

       View header = (View)getLayoutInflater().inflate(R.layout.header, null);
        lv1.addHeaderView(header);

        lv1.setAdapter(adapter);
        return v;
    }
}

现在在这里，我收到一个错误“

Fragment 类型中的 getLayoutInflater(Bundle) 方法不适用于 arguments()

“在行中

View header = (View)getLayoutInflater().inflate(R.layout.header, null);

我该如何解决这个错误？谢谢

4

1 回答 1

3

改变

View header = (View)getLayoutInflater().inflate(R.layout.header, null);

和

  View header = inflater.inflate(R.layout.header, null);

的第一个参数onCreatView是LayoutInflater

于 2013-07-16T07:04:59.320 回答