-1

嗨，我正在使用（JPA）为一个对象用户开发持久层，我正在编辑器中编写代码，而不是使用 spring hibernate 我编写了以下代码，但它显示包 javax.persistence。*；没有找到我如何使它工作可以帮助任何人。

这是我写的课。

//import javax.persistence.*;
import java.io.Serializable;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.NamedQueries;
import javax.persistence.NamedQuery;

@Entity(name = "USER") //Name of the entity

public class User implements Serializable
{
    private int userId;
    private String userName;
    private String password;
    private String firstName;
    private String lastName;
    private String roles;

    @Id
    @Column(name = "USER_ID", nullable = false)    
    public int getUserId()
    {
        return userId;
    }

    public void setUserId(int UserId) 
    {
        this.userId = userId;
    }

    @Column(name = "USER_NAME", nullable = false)
    public String getUserName()
    {
        return userName;
    }

    public void setUserName(int userName) 
    {
        this.userName = userName;
    }

    @Column(name = "PASSWORD", nullable = false)
    public String getPassword()
    {
        return password;
    }

    public void setPassword(int password) 
    {
        this.password = password;
    }

    @Column(name = "FIRST_NAME", nullable = false)
    public String getFirstName()
    {
        return firstName;
    }

    public void setFirstName(int firstName) 
    {
        this.firstName = firstName;
    }

    @Column(name = "LAST_NAME", nullable = false)
    public String getLastName()
    {
        return lastName;
    }

    public void setLastName(int lastName) 
    {
        this.lastName = lastName;
    }

    @Column(name = "ROLES", nullable = false)
    public String getRoles()
    {
        return roles;
    }

    public void setRoles(int roles) 
    {
        this.roles = roles;
    }

    public User() 
    {
    }

}
4

2 回答 2

2

将持久性 API添加到您的构建路径

于 2013-07-16T05:51:08.407 回答
1

您必须在类路径中设置 persistence.jar。

于 2013-07-16T05:52:06.803 回答