2

我正在使用strsplit(大概)内存不足;这是代码:

split.fields <- function (frame, fields, split, suffix, ...) {
  for (field in fields) {
    v <- sapply(strsplit(frame[[field]],"@",...),"[",1)
    frame[[paste0(field,suffix)]] <- frame[[field]]
    frame[[field]] <- v
  }
  frame
}
split.version <- function (frame, fields)
  split.fields(frame, fields, split="@", suffix="Ver", fixed=TRUE)
> gc()
         used (Mb) gc trigger (Mb) max used (Mb)
Ncells 238165 12.8     467875   25   407500 21.8
Vcells 369492  2.9     905753    7   905631  7.0
> frame <- data.frame(browser = sample(c("Chrome@28","Chrome@27","Firefox@21","Firefox@22","IE@9","IE@8"), 1e7, replace=TRUE), stringsAsFactors=FALSE)
> str(frame)
'data.frame':   10000000 obs. of  1 variable:
 $ browser: chr  "IE@8" "Chrome@27" "Chrome@27" "Chrome@27" ...
> object.size(frame)
80000992 bytes
> gc()
           used (Mb) gc trigger  (Mb) max used  (Mb)
Ncells   240555 12.9     467875  25.0   407500  21.8
Vcells 10373979 79.2   34109873 260.3 40534688 309.3
> system.time(frame <- split.version(frame,"browser"))
   user  system elapsed 
 73.700   0.872  74.831 
> object.size(frame)
160001248 bytes
> str(frame)
'data.frame':   10000000 obs. of  2 variables:
 $ browser   : chr  "IE" "Chrome" "Chrome" "Chrome" ...
 $ browserVer: chr  "IE@8" "Chrome@27" "Chrome@27" "Chrome@27" ...
> gc()
           used  (Mb) gc trigger  (Mb)  max used   (Mb)
Ncells   264888  14.2   16652260 889.4  31376740 1675.7
Vcells 20459856 156.1   95461025 728.4 119226749  909.7

R除了进程的 RSS 现在是1.6G之外,这一切看起来或多或少都是合理的。

这似乎意味着该列中 1675.7Mb 的 Ncellmax used 尚未返回给操作系统。

我不太关心操作系统没有取回 RAM,我关心的是处理 80M 的数据 R 分配了 1.6G(并且在我的真实数据上它用完了可用的物理 RAM)

有没有办法提高内存效率?

例如,也许将字符向量转换为因子并在其级别上进行操作会有所帮助?

R version 3.0.1 (2013-05-16) -- "Good Sport"
Platform: x86_64-pc-linux-gnu (64-bit)
4

2 回答 2

4

如何使用substrand regexpr

x <- c("Chrome@28","Chrome@27","Firefox@21","IE@8")
substr(x,1,regexpr("@",x)-1)
[1] "Chrome"  "Chrome"  "Firefox" "IE" 
于 2013-07-15T17:38:35.723 回答
3

@James 说了什么,甚至更简单:

x <- c("Chrome@28","Chrome@27","Firefox@21","IE@8")
sub('@.*', '', x)
#[1] "Chrome"  "Chrome"  "Firefox" "IE"  
于 2013-07-15T17:42:04.883 回答