javascript - 如何编辑 js 对象/函数

Question

嗨，我正在使用一个 api，但我应该为它打一个补丁

Songapi.prototype.goPlaySong=Songapi.prototype.goPlaySong.toString().replace('["universal","emi","warner"]) !== -1','false');

没用也试过

Songapi.prototype.goPlaySong=Function(Songapi.prototype.goPlaySong.toString().replace('["universal","emi","warner"]) !== -1','false'));

或者

Songapi.prototype.goPlaySong=eval(Songapi.prototype.goPlaySong.toString().replace('["universal","emi","warner"]) !== -1','false'));

还是想不通？

Answer 1

演示

SongApiconstructor又名一类。

function inherits(child, parent) {
  function temp() {};
  temp.prototype = parent.prototype;
  child.prototype = new temp();
  child.prototype.constructor = child;
};

var CustomizedApi = function() {
    SongApi.call(this);
};
inherits(CustomizedApi, Songapi);
// or use Object.create for inheritance.
CustomizedApi.prototype = Object.create(SongApi.prototype);

/**
 * @override
 */
CustomizedApi.prototype.goPlaySong = function() {
   // override with whatever you want.
};
var api = new CustomizedApi;
api.goPlaySong();

Answer 2

尝试 ：

eval('var code = ' + Songapi.prototype.goPlaySong.toString().replace('["universal","emi","warner"]) !== -1','false'));

Songapi.prototype.goPlaySong = code;

但这绝对是肮脏的。

Answer 3

var newgoPlaySong=Songapi.prototype.goPlaySong.toString().replace('$.inArray(response.provider,["universal","emi","warner"]) !== -1','false');
eval('Songapi.prototype.goPlaySong = '+gecicigoPlaySong+';');

它起作用了，谢谢