我有这个代码。该脚本在 ajax 成功时返回 true，但它不会将此值返回给函数，因此无法提交表单。请问有人可以帮忙吗？
更新：我修改了脚本：
jQuery代码：
$(document).ready(function () {
$('#addForm').live('submit', function (e) {
e.preventDefault();
$(".error").remove();
var client_name = $("#client_name").val();
var project_name = $('#project_name').val();
var source_lang = $('#source_lang option:selected').length;
var job_no = $('#job_no').val();
var targ_lang = $('#targ_lang option:selected').length;
var supplier_id = $('supplier_id option:selected').length;
var start_date = $('#start_date').val();
var deadline = $('#deadline').val();
var targ_lang_val = $('#targ_lang option:selected').val();
var source_lang_val = $('#source_lang option:selected').val();
var haserror = false;
$.ajax({
type : "GET",
dataType : 'json',
async : false,
url : "file.php?job=" + job_no + "&client_name=" + client_name + "&project_name=" + project_name + "&source_lang=" + source_lang + "&targ_lang=" + targ_lang + "&supplier_id=" + supplier_id + "&start_date=" + start_date + "&deadline=" + deadline + "&targ_lang_val=" + targ_lang_val + "&source_lang_val=" + source_lang_val,
success : function (data) {
$.each(data, function (index, element) {
if (index == 'job_no') {
if (element == true) {
$("#" + index).after('<br><span class="error" style="color: red;">This Job No already exists.</span><br>');
haserror = true;
} else
haserror = false;
}
if (element == true) {
$("#" + index).after('<br><span class="error" style="color: red;">This field is required.</span><br>');
haserror = true;
} else
haserror = false;
});
return !haserror;
}
});
});
});
服务器端PHP 代码：
$client_name = $_GET['client_name'];
$deadline = $_GET['deadline'];
if ($client_name == '') {
$hasError['client_name'] = true;
} else
$hasError['client_name'] = false;
// .........................
if ($deadline == '') {
$hasError['deadline'] = true;
} else
$hasError['deadline'] = false;
print json_encode($hasError);