7

我有一组 KeyValuePair 项,其中 DateTime 作为键,字符串作为值。基本上我的数据看起来像:

12/07/2013 - 10220
12/07/2013 - 10220
12/07/2013 - 12220
12/07/2013 - 11240
12/07/2013 - 15220
13/07/2013 - 23220
13/07/2013 - 35620
14/07/2013 - 15620
14/07/2013 - 15620

我想要一份我每天有多少物品(不同)的清单。所以查询将导致:

12/07/2013 - 4
13/07/2013 - 2
14/07/2013 - 1
4

2 回答 2

18

采用group by

var dateGrouped = dates.GroupBy(x => x.Key)
                       .Select(x => new { Date = x.Key, Values = x.Distinct().Count() });
于 2013-07-15T10:44:32.490 回答
3

以下是完整示例的解决方案

        var list = new[]
        {
            new {Date = new DateTime(2013,07,12), value = 10220},
            new {Date = new DateTime(2013,07,12), value = 10220},
            new {Date = new DateTime(2013,07,12), value = 12220},
            new {Date = new DateTime(2013,07,12), value = 11240},
            new {Date = new DateTime(2013,07,12), value = 15220},
            new {Date = new DateTime(2013,07,13), value = 23220},
            new {Date = new DateTime(2013,07,13), value = 35620},
            new {Date = new DateTime(2013,07,14), value = 15620},
            new {Date = new DateTime(2013,07,14), value = 15620},
        };


        var res = from l in list group l by new { l.Date } into g select new { g.Key.Date, value = g.Distinct().Count() };

        foreach (var item in res)
        {
            Console.WriteLine(item.Date + " " + item.value);
        }
于 2013-07-15T11:13:56.243 回答