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我计算了该表中元素退出的数量,但它不起作用?我尝试这样

alert($('.caseName_h').val());

我对这个 val 有所警觉;在该代码中断之后

var tt  =tx.executeSql('SELECT 1 FROM CaseTable WHERE CaseName ='+"'+ $('.caseName_h').val()+'");

我也这样调用 var tt =tx.executeSql('SELECT 1 FROM CaseTable WHERE CaseName ='+ $(".caseName_h").val()); 警报(tt)

未定义来

4

1 回答 1

1

尝试这样的事情......

db.transaction(function (tx) {
            var caseName_h = $('.caseName_h').val();
            $yoursql = 'SELECT 1 FROM CaseTable WHERE CaseName = "'+caseName_h+'"';
            tx.executeSql($yoursql, [], function (tx, results) {
                if ( results.rows.length == 0 ) {
                    console.log(results.rows);
                }
            });
});
于 2013-07-15T09:16:20.667 回答