10

编辑完全重新处理问题以便更好地理解

我必须http://api.bf3stats.com/pc/player/使用 2 个 POST 参数查询给定的 url：'player'（用于玩家名称）和 'opt'（用于选项）。我已经在http://www.requestmaker.com/上使用以下数据对其进行了测试：player=Zer0conf&opt=all. 我得到了正确的 JSON 响应（以为我不知道他们的网站如何执行查询，我猜是 php）。现在我正在尝试在 Android 中做同样的事情：

  private StringBuilder inputStreamToString(InputStream is) {
       //this method converts an inputStream to String representation
    String line = "";
    StringBuilder total = new StringBuilder();

    BufferedReader rd = new BufferedReader(new InputStreamReader(is));

    try {
        while ((line = rd.readLine()) != null) {
            total.append(line);
        }
    } catch (IOException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }

    return total;
}

这就是我提出请求的方式：

 public void postData(String url, String name) {

    HttpClient httpclient = new DefaultHttpClient();
    HttpPost httppost = new HttpPost(url);

    try {

        List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
                    //qname is a String containing a correct player name
        nameValuePairs.add(new BasicNameValuePair("player", qname));
        nameValuePairs.add(new BasicNameValuePair("opt", "all"));
        httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));

        HttpResponse response = httpclient.execute(httppost);
        //test is just a string to check the result, which should be in JSON format
        test = inputStreamToString(response.getEntity().getContent())
                .toString();

    } catch (ClientProtocolException e) {

    } catch (IOException e) {

    }
}

我在“测试”字符串中得到的不是 JSON，而是某些 bf3stats 页面的完整 HTML 标记。我的请求可能有什么问题？

在此处输入图像描述

4

2 回答 2

14

您需要"application/x-www-form-urlencoded"在请求标头中为要发送的数据类型设置内容类型。

我针对上述数据测试了您的 API，它工作正常，并且我收到了大量数据作为响应。你可以在这里找到它。

您可以尝试以下代码：

public  String postDataToServer(String url) throws Throwable
    {

    HttpPost request = new HttpPost(url);
    StringBuilder sb=new StringBuilder();

    String requestData = prepareRequest();
    StringEntity entity = new StringEntity(requestData);
                         entity.setContentType("application/x-www-form-urlencoded;charset=UTF-8");//text/plain;charset=UTF-8
                         request.getParams().setParameter(CoreProtocolPNames.USE_EXPECT_CONTINUE, Boolean.FALSE);

                         request.setHeader("Accept", "application/json");
                         request.setEntity(entity); 
                         // Send request to WCF service 
                         HttpResponse response =null;
                         DefaultHttpClient httpClient = new DefaultHttpClient();
                         //DefaultHttpClient httpClient = getNewHttpClient();
                         HttpConnectionParams.setSoTimeout(httpClient.getParams(), 10*1000); 
                         HttpConnectionParams.setConnectionTimeout(httpClient.getParams(),10*1000); 
                         try{

                         response = httpClient.execute(request); 
                         }
                         catch(SocketException se)
                         {
                             Log.e("SocketException", se+"");
                             throw se;
                         }
                         /* Patch to prevent user from hitting the request twice by clicking 
                          * the view [button, link etc] twice.
                          */
                         finally{
                         }



    InputStream in = response.getEntity().getContent();
    BufferedReader reader = new BufferedReader(new InputStreamReader(in));
    String line = null;
    while((line = reader.readLine()) != null){
        sb.append(line);

    }
    Log.d("response in Post method", sb.toString()+"");
    return sb.toString();
    }

    public String prepareRequest()
    {

        return "player=Zer0conf&opt=all";
    }

编辑： 我收到错误Expectation Failed error- 417 for your Webservice。所以我们需要在我们的请求中再添加一个参数。它是request.getParams().setParameter(CoreProtocolPNames.USE_EXPECT_CONTINUE, Boolean.FALSE);。我已经用这个更新了上面的代码。现在它工作正常。

响应看起来像这样。

响应看起来像这样。

希望这会有所帮助。

干杯
N_JOY

于 2013-07-17T21:04:58.940 回答
0

尝试在浏览器中查看 url，我相信有一个 !DOCTYPE 声明，它肯定无法解析为 JSON 对象。

于 2013-07-15T02:53:27.887 回答