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我需要帮助解决我遇到的这个问题。我试图让我的程序从每一行的第一个单词中获取第一个字母并将它们打印在一个字符串中。

例如，如果我在一段文本中键入以下单词：

People like to eat pie for three reasons, it tastes delicious. The taste is unbelievable, next pie makes a
great dessert after dinner, finally pie is disgusting.

结果应该是“Pg”这是一个小例子，但你明白了。

我从代码开始，但我不知道该去哪里。

#Prompt the user to enter a block of text.
done = False
print("Enter as much text as you like. Type EOF on a separate line to finish.")
textInput = ""
while(done == False):
    nextInput= input()
    if nextInput== "EOF":
        break
    else:
        textInput += nextInput

#Prompt the user to select an option from the Text Analyzer Menu.
print("Welcome to the Text Analyzer Menu! Select an option by typing a number"
    "\n1. shortest word"
    "\n2. longest word"
    "\n3. most common word"
    "\n4. left-column secret message!"
    "\n5. fifth-words secret message!"
    "\n6. word count"
    "\n7. quit")

#Set option to 0.
option = 0

#Use the 'while' to keep looping until the user types in Option 7.
while option !=7:
    option = int(input())

#I have trouble here on this section of the code.
#If the user selects Option 4, extract the first letter of the first word
    #on each line and merge into s single string.
    elif option == 4:
        firstLetter = {}
        for i in textInput.split():
            if i < 1:
                print(firstLetter)
4

3 回答 3

0

您可以将输入存储为列表，然后从每个列表中获取第一个字符：

textInput = []
while(done == False):
    nextInput= input()
    if nextInput== "EOF":
       break
    else:
        textInput.append(nextInput)



...


print ''.join(l[0] for l in textInput)
于 2013-07-15T02:07:33.590 回答
0

我首先制作一个行列表而不是单个字符串：

print("Enter as much text as you like. Type EOF on a separate line to finish.")

lines = []

while True:
    line = input()

    if line == "EOF":
        break
    else:
        lines.append(line)

然后，您可以通过循环获取第一个字母：

letters = []

for line in lines:
    first_letter = line[0]
    letters.append(first_letter)

print(''.join(letters))

或更简洁地说：

print(''.join([line[0] for line in lines]))
于 2013-07-15T02:07:53.063 回答
-1

这很简单：

with open('path/to/file') as infile:
    firsts = []
    for line in infile:
        firsts.append(line.lstrip()[0])
print ''.join(firsts)

当然，你可以用下面的两条线做同样的事情：

with open('path/to/file') as infile:
    print ''.join(line.lstrip()[0] for line in infile)

希望这可以帮助

于 2013-07-15T02:28:18.273 回答