这段代码有错误吗？ 这里的例子
我尝试制作相同的示例，但效果不佳
如果有任何机构可以通过发送教程或任何帮助来帮助我，我想从数据库发出实时通知
注意：我使用 wamp 服务器在 localhost 上工作
HTML
索引.php
<!doctype html>
<html>
<head>
<script type="text/javascript" src="js/jquery.js"></script>
<script>
var timestamp = null;
function waitForMsg () {
$.ajax({
type: "GET",
url: "getData.php?timestamp="+timestamp,
async: true,
cache : false,
success : function (data){
var json = eval('(' + data + ')');
if (json['msg'] != "") {
alert(json['msg']);
}
timestamp = json['timestamp'];
setTimeOut("waitForMsg()" , 1000);
},
erorr : function (XMLHttpRequest,textStatus, erorrThrown) {
alert("erorr :" + textStatus + "(" + erorrThrown + ")");
setTimeOut("waitForMsg()", 15000);
}
});
}
$(document).ready(function(){
waitForMsg();
});
</script>
</head>
<body>
</body>
</html>
PHP
获取数据.php
<?php
$filename = dirname(__FLIE__)."/data.txt";
$lastmodif = isset($_GET['timestamp']) ? $_GET['timestamp'] : 0;
$currentmodif = filemtime($filename);
while($currentmodif <= $lastmodif){
usleep(10000);
clearstatcache();
$currentmodif = filemtime($filename);
}
$response = array();
$response['msg'] = file_get_contents($filename);
$response['timestamp'] = currentmodif();
echo json_encode($response);
?>