这是我的问题:polyfit不采用日期时间值,因此我转换了日期时间并mktime生成多项式拟合作品
z4 = polyfit(d, y, 3) 
p4 = poly1d(z4)
然而,对于情节,我想要轴上的日期时间描述,并没有 # 弄清楚如何做到这一点。你能帮助我吗?
fig = plt.figure(1)
cx= fig.add_subplot(111) 
xx = linspace(0,  d[3], 100)
pylab.plot(d, y, '+', xx, p4(xx),'-g')
cx.plot(d, y,'+', color= 'b', label='blub')
plt.errorbar(d, y,
           yerr,
           marker='.',
           color='k',
           ecolor='b',
           markerfacecolor='b',
           label="series 1",
           capsize=0,
           linestyle='')
cx.grid()
cx.set_ylim(0,0.03)
plt.show()
其余代码:
import numpy as np
import matplotlib.pyplot as plt
from matplotlib import axis
from datetime import datetime
from numpy import *
import pylab
import time
我的前 4 个时间数据点
x = [datetime(1978, 7, 7), 
     datetime(1980, 9, 26), 
     datetime(1983, 8, 1), 
     datetime(1985,8,8)]
d=[]
for i in x:
    d.append(time.mktime(i.timetuple()))
我的前 4 个数据值
y = [0.00134328779552718,
     0.00155187668863844,
     0.0039431374327427,
     0.00780037563783297]
我计算的误差线标准偏差
yerr = [0.0000137547160254577,
        0.0000225670232594083,
        0.000105623642510075,
        0.00011343121508]
