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我有几个问题。我希望能够获取放在一起的所有事件的最小值 [最早] (start_time)和最大值 [最新] (end_time)，但是，我只想选择日期发生的事件的最大值和最小值下面.... ($date0_post)... [请注意，我将复制这七次，以复制一周的风格...所以“+0 日”最终将具有一个功能，即：“+1 天”、“+2 天”等]

$date0 = strtotime("+0 day");
$date0_post = date('Y-m-d', $date0);

下面是我认为它可能如何工作的一个例子，但是，我确信我做错了：

$sql = "SELECT max(end_time), min(start_time) FROM events WHERE date='$date0_post' AND course='$courseid'";
$query = mysqli_query($db_conx, $sql);
while($row = mysqli_fetch_assoc($query)){
$event_min_start = $row["start_time"];    
$event_max_end = $row["end_time"];
}

另外，我有变量$coursetee_open_time_mysql和$coursetee_close_time_mysql ...日期时间格式（这些最大值和最小值的格式相同）...下面是一个 if 语句，声明如果：
任何事件的 MIN-START 时间那一天比课程的开放时间早，当天任何活动的最大结束时间都比关闭时间早，然后echo '<option value="1" disabled>Closed for '.$closed_reason.'</option>';

if ($event_min_start < $coursetee_open_time_mysql && $coursetee_close_time_mysql < $event_max_end) {
echo '<option value="1" disabled>Closed for '.$closed_reason.'</option>';
} else {
echo '<option value="1">Today</option>';
}
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1 回答 1

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I was over thinking it, I fixed it and turned three fetches into one...thankyou @hd1 for leading me in the correct dirrection.

$sql = "select reason, min(start_time) AS start_time, max(end_time) AS end_time FROM events WHERE date='$date_post' AND course='$courseid'";
$query = mysqli_query($db_conx, $sql);
while($row = mysqli_fetch_assoc($query)){
$event_max_end = $row["end_time"];
$event_min_start = $row["start_time"];
$event_reason = $row["reason"];
}
于 2013-07-15T03:13:33.870 回答