9

我想使用 laravel 的 DB 类来执行 mysql 查询，但是 Laravel 提供的功能都不起作用。

这些都不起作用： DB::statment() / DB::select() / DB::raw() / DB::update() / DB::select(DB::raw())

这是我想查询的代码：

DROP TABLE users;

CREATE TABLE `users` (
  `id` int(10) unsigned NOT NULL AUTO_INCREMENT,
  `u_username` varchar(255) COLLATE utf8_unicode_ci NOT NULL,
  `u_email` varchar(255) COLLATE utf8_unicode_ci NOT NULL,
  `password` varchar(255) COLLATE utf8_unicode_ci NOT NULL,
  `u_regdate` datetime NOT NULL DEFAULT '0000-00-00 00:00:00',
  `u_birthday` date NOT NULL DEFAULT '0000-00-00',
  `u_lastlogin` int(11) NOT NULL,
  `u_logcout` int(11) NOT NULL DEFAULT '0',
  `u_level` tinyint(1) NOT NULL DEFAULT '0',
  `u_language` tinyint(1) NOT NULL DEFAULT '0',
  `u_status` tinyint(1) NOT NULL DEFAULT '0',
  `u_gender` tinyint(1) NOT NULL DEFAULT '0',
  PRIMARY KEY (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=6 DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci;

INSERT INTO users VALUES("1","admin","admin@example.com","$2y$08$9sBJh7iyF9Yr6xvsieNmBOsotGPBkZFydVjb/Yk5Fzh4IGBVo7Je6","0000-00-00 00:00:00","0000-00-00","0","0","9","0","0","0");
INSERT INTO users VALUES("2","moderator","mod@example.com","$2y$08$15/tIKPM/8gATSzkmey5tuAA/PL4lJeFq7liTETyz0h1dkOotwp3G","0000-00-00 00:00:00","0000-00-00","0","0","0","0","0","0");
INSERT INTO users VALUES("3","helper","help@example.com","$2y$08$nTtZU9/UBeRLbYJRO/XwCe2D/B57ofx2bCN8vGEiHkqO.bPra0WT6","0000-00-00 00:00:00","0000-00-00","0","0","0","0","0","0");
INSERT INTO users VALUES("4","dude12","dude@example.com","$2y$08$y0JweKtWxJFRF7Ko8q0zkODY.EWEKJ.CR1dDco6aCJh8ssKdzQ6RC","0000-00-00 00:00:00","0000-00-00","0","0","0","0","0","0");
INSERT INTO users VALUES("5","girl1","girl@example.com","$2y$08$UKjJzxDuYW7upqeLsm1VOOo2jUoqMaai0/1jFxvLDzC6eWjin3yOe","0000-00-00 00:00:00","0000-00-00","0","0","0","0","0","0");

我也看过并尝试了这两个主题的方法，但没有任何效果：

无法在 laravel-4 中运行原始查询

laravel-4-how-to-run-a-raw-sql

使用 "DB::select( DB::raw($query) )" 或 DB::statement 执行时返回错误：

SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'CREATE TABLE `users` ( `id` int(10) unsigned NOT NULL AUTO_INCREMENT, `u_use' at line 3 (SQL: DROP TABLE users; CREATE TABLE `users` ( `id` int(10) unsigned NOT NULL AUTO_INCREMENT, `u_username` varchar(255) COLLATE utf8_unicode_ci NOT NULL, `u_email` varchar(255) COLLATE utf8_unicode_ci NOT NULL, `password` varchar(255) COLLATE utf8_unicode_ci NOT NULL, `u_regdate` datetime NOT NULL DEFAULT '0000-00-00 00:00:00', `u_birthday` date NOT NULL DEFAULT '0000-00-00', `u_lastlogin` int(11) NOT NULL, `u_logcout` int(11) NOT NULL DEFAULT '0', `u_level` tinyint(1) NOT NULL DEFAULT '0', `u_language` tinyint(1) NOT NULL DEFAULT '0', `u_status` tinyint(1) NOT NULL DEFAULT '0', `u_gender` tinyint(1) NOT NULL DEFAULT '0', PRIMARY KEY (`id`) ) ENGINE=InnoDB AUTO_INCREMENT=6 DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci; INSERT INTO users VALUES("1","admin","admin@example.com","$2y$08$9sBJh7iyF9Yr6xvsieNmBOsotGPBkZFydVjb/Yk5Fzh4IGBVo7Je6","0000-00-00 00:00:00","0000-00-00","0","0","9","0","0","0"); INSERT INTO users VALUES("2","moderator","mod@example.com","$2y$08$15/tIKPM/8gATSzkmey5tuAA/PL4lJeFq7liTETyz0h1dkOotwp3G","0000-00-00 00:00:00","0000-00-00","0","0","0","0","0","0"); INSERT INTO users VALUES("3","helper","help@example.com","$2y$08$nTtZU9/UBeRLbYJRO/XwCe2D/B57ofx2bCN8vGEiHkqO.bPra0WT6","0000-00-00 00:00:00","0000-00-00","0","0","0","0","0","0"); INSERT INTO users VALUES("4","dude12","dude@example.com","$2y$08$y0JweKtWxJFRF7Ko8q0zkODY.EWEKJ.CR1dDco6aCJh8ssKdzQ6RC","0000-00-00 00:00:00","0000-00-00","0","0","0","0","0","0"); INSERT INTO users VALUES("5","girl1","girl@example.com","$2y$08$UKjJzxDuYW7upqeLsm1VOOo2jUoqMaai0/1jFxvLDzC6eWjin3yOe","0000-00-00 00:00:00","0000-00-00","0","0","0","0","0","0"); ) (Bindings: array ( ))
4

3 回答 3

25

像我在问题中提供的那样执行 SQL 代码可以使用

DB::unprepared( $code );

我希望这可以帮助有同样问题的人：D

查看 laravel 问题时找到的答案

于 2013-07-13T14:08:17.937 回答
2

从数据库中删除用户表，然后试试这个，让我知道它是否有效：

DB::insert('CREATE TABLE `users` (
  `id` int(10) unsigned NOT NULL AUTO_INCREMENT,
  `u_username` varchar(255) COLLATE utf8_unicode_ci NOT NULL,
  `u_email` varchar(255) COLLATE utf8_unicode_ci NOT NULL,
  `password` varchar(255) COLLATE utf8_unicode_ci NOT NULL,
  `u_regdate` datetime NOT NULL DEFAULT '0000-00-00 00:00:00',
  `u_birthday` date NOT NULL DEFAULT '0000-00-00',
  `u_lastlogin` int(11) NOT NULL,
  `u_logcout` int(11) NOT NULL DEFAULT '0',
  `u_level` tinyint(1) NOT NULL DEFAULT '0',
  `u_language` tinyint(1) NOT NULL DEFAULT '0',
  `u_status` tinyint(1) NOT NULL DEFAULT '0',
  `u_gender` tinyint(1) NOT NULL DEFAULT '0',
  PRIMARY KEY (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=6 DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci');

//and so on for all the other queries.
于 2013-07-13T13:50:40.307 回答
2

这段代码呢？我发现使用迁移和数据库播种非常有用- 特别是对于部署。

Schema::create('users', function($table){
    $table->increments('id');
    $table->string('u_username');
    $table->string('u_email');
    $table->string('password');
    $table->datetime('u_regdate');
    $table->date('u_birthday');
    $table->integer('u_lastlogin');
    $table->integer('u_logcout')->default(0);
    $table->tinyinteger('u_level')->default(0);
    $table->tinyinteger('u_language')->default(0);
    $table->tinyinteger('u_status')->default(0);
    $table->tinyinteger('u_gender')->default(0);
});


// Repeat this for other users as well
User::create([
    'u_username' =>     'admin',
    'u_email' =>        'admin@example.com',
    'password' =>       Hash::make('users-password'),
    'u_regdate' =>      date('Y-m-d H:i:s'),
    'u_birthday' =>     '1980-01-01',
    'u_lastlogin' =>    0,
    'u_logcout' =>      0,
    'u_level' =>        9,
    'u_language' =>     0,
    'u_status' =>       0,
    'u_gender' =>       0,
]);
于 2013-07-13T21:01:30.073 回答