c++ - 简单数组未通过

Question

int i;
int b = 0;
int a[20];


for (i = 0; i < 20; i++){
a[i] = b+1;
cout << a[i];}



 }

//我知道这是一个简单的程序，但它没有给出预期的输出，也没有单步执行程序或打印出结果

Answer 1

Your loop keeps assigning a[i] without changing b. Since b stays at zero, all as are going to be 1 (because b is zero, b+1 is 1).

If you would like to assign sequential values, either use the loop index i, or change b in the body of the loop:

for (i = 0; i < 20; i++) {
    a[i] = i+1;
}

or

for (i = 0; i < 20; i++) {
    a[i] = ++b; // Adds 1 to b, and changes b for the next iteration.
}

Answer 2

You are printing out the wrong variable. This should work:

int i;
int a[20];


for (i = 0; i < 20; i++){
a[i] = i+1;
cout << a[i];}

Answer 3

如果您希望通过以下方式分配，您可以这样做b：

int i;
int b = 1;
int a[20];



for (i = 0; i < 20; i++){
a[i] = b;
cout << a[i];
b++;}