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我有两个单独的代码： 1. 一个表单在按钮单击时显示数据库的内容 (form.php) 2. 另一个 php 页面显示图表到 div 中，在加载时从 mysql 数据库中检索内容。(graph.php)

我是ajax的新手。我试图在另一个 php 页面的（form.php）div 上显示图表，其代码存在于 graph.php 中。

问题是graph.php，它显示加载事件的图表使用同一页面本身（graph.php）中存在的div id来显示图表。如何在 form.php 中的 div 中加载此页面

表单.php

<html><head><script>
function showUser(str)
{
if (str=="")
  {
  document.getElementById("txtHint").innerHTML="";
  return;
  }
if (window.XMLHttpRequest)
  {// code for IE7+, Firefox, Chrome, Opera, Safari
  xmlhttp=new XMLHttpRequest();
  }
else
  {// code for IE6, IE5
  xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
  }
xmlhttp.onreadystatechange=function()
  {
  if (xmlhttp.readyState==4 && xmlhttp.status==200)
    {
    document.getElementById("txtHint").innerHTML=xmlhttp.responseText;
    }
  }
xmlhttp.open("GET","graph.php?q="+str,true);
xmlhttp.send();
}
</script>
</head>
<body>
<form>
<input type="submit"onclick="showUser(this.value)"/>
</form>
<br>
<div id="txtHint"><b>Person info will be listed here.</b></div>
</body>
</html>

另一个从 db 加载数据并使用谷歌图表 API 显示图表的页面是 graph.php：

<?php
$q=$_GET["q"];
  $mysqli =mysqli_connect('127.0.0.1:3306', 'root', 'root', 'test');
if (mysqli_connect_errno()) {
    echo "Failed to connect to MySQL: ".mysqli_connect_error();
}

  $result = $mysqli->query('SELECT * FROM new_temp');
  $rows = array();
  $table = array();
  $table['cols'] = array(

    array('label' => 'ind_type', 'type' => 'string'),
    array('label' => 'sum', 'type' => 'number')

);
    /* Extract the information from $result */
    foreach($result as $r) {

      $temp = array();
      $temp[] = array('v' => (string) $r['ind_type']); 
      $temp[] = array('v' => (int) $r['sum']); 
      $rows[] = array('c' => $temp);
    }

$table['rows'] = $rows;
$jsonTable = json_encode($table);
?>
<html>
  <head>
    <!--Load the Ajax API-->
    <script type="text/javascript" src="https://www.google.com/jsapi"></script>
    <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.8.2/jquery.min.js"></script>
    <script type="text/javascript">

    // Load the Visualization API and the piechart package.
    google.load('visualization', '1', {'packages':['corechart']});

    // Set a callback to run when the Google Visualization API is loaded.
    google.setOnLoadCallback(drawChart);

    function drawChart() {
var data = new google.visualization.DataTable(<?=$jsonTable?>);
      var options = {
           title: 'Index analysis',
          is3D: 'true',
          width: 800,
          height: 600
        };
      var chart = new google.visualization.PieChart(document.getElementById('txtHint'));
      chart.draw(data, options);
    }
    </script>
  </head>

  <body>
    <!--this is the div that will hold the pie chart-->
    <div id="txtHint"></div>
  </body>
</html>
4

1 回答 1

1

first you must make all data with json on php file, include jquery on html then use this code : i hope it will help you

HTML 

<form action="graph.php" method="get">
  <input type="text" name="q" />
  <input type="submit"/>
</form>

js

$("form").on("submit", function(){
 $.get($('form').attr('action'), $('form').serialize(), 
     function(result) {
         $("#txtHint").html(result);
      },'json');
 });
于 2013-07-13T03:06:51.047 回答