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我有 3 个表用户、产品和销售

user
UID | NAME
 1  | agent1
 2  | agent2
 3  | agent3
 4  | agent4
 5  | agent5

products
PID | PNAME
 1  |   P1
 2  |   P2
 3  |   P3

sales
SID | UID | PID | SALES_CREATED
 1  |  3  |  1  | 2013-07-13 01:15:04
 2  |  1  |  1  | 2013-07-13 01:25:34
 3  |  3  |  1  | 2013-07-13 02:01:34
 4  |  3  |  1  | 2013-07-13 02:45:34
 5  |  5  |  1  | 2013-07-13 02:56:34
 6  |  5  |  1  | 2013-07-13 03:21:34
 7  |  2  |  3  | 2013-07-13 03:38:34
 8  |  3  |  2  | 2013-07-13 03:51:34
 9  |  4  |  2  | 2013-07-13 04:25:34
 10 |  3  |  1  | 2013-07-13 04:45:04
 11 |  1  |  3  | 2013-07-13 04:55:34
 12 |  2  |  2  | 2013-07-13 05:01:34
 13 |  1  |  3  | 2013-07-13 05:15:34
 14 |  5  |  3  | 2013-07-13 05:36:34
 15 |  5  |  3  | 2013-07-13 06:21:34

每个代理的销售结果是：（按用户 UID 排序）

  user   | P1 | P2 | P3 |
 agent1  | 1  | 0  | 2  |
 agent2  | 0  | 1  | 1  |
 agent3  | 4  | 1  | 0  |
 agent4  | 0  | 1  | 0  |
 agent5  | 2  | 0  | 2  |

现在，我想要一个结果来对 P1 销售额最大且最少 3 个结果的用户进行排序，结果将是这样的

  user   | P1 | P2 | P3 |
 agent3  | 4  | 1  | 0  |
 agent5  | 2  | 0  | 2  |
 agent1  | 1  | 0  | 2  |

你们能给我一个最好的mysql_query来显示这个结果吗？

4

2 回答 2

1

哦，像这样的东西……

 SELECT uid
      , SUM(pid=1) p1
      , SUM(pid=2) p2
      , SUM(pid=3) p3 
   FROM sales 
  GROUP 
     BY uid 
  ORDER 
     BY p1 DESC
      , p2 DESC
      , p3 DESC;
 +-----+------+------+------+
 | uid | p1   | p2   | p3   |
 +-----+------+------+------+
 |   3 |    4 |    1 |    0 |
 |   5 |    2 |    0 |    2 |
 |   1 |    1 |    0 |    2 |
 |   2 |    0 |    1 |    1 |
 |   4 |    0 |    1 |    0 |
 +-----+------+------+------+

如果在应用程序级别处理显示逻辑，那么您的查询可以简化为更具可扩展性的内容，例如......

 SELECT uid
      , pid
      , COUNT(*)
   FROM sales 
  GROUP 
     BY uid,pid;
于 2013-07-12T21:28:53.473 回答
1

我只是回答，因为（1）我很无聊，（2）我想要一个脑筋急转弯练习。我通常不喜欢在人们发布和运行时回答（不回复任何人的评论/帖子），或者提供他们尝试过的内容（不询问）。
如果您希望将来对 SO 有更好/更多的帮助，发布您尝试过的查询以及使用这样的复杂/多样化数据创建 sqlfiddle - http://sqlfiddle.com/将是有益的

所以有了这个警告，这里是你如何获得你想要的结果

SELECT 
   user.NAME as user, 
   SUM(PID=1) as P1,
   SUM(PID=2) P2,
   SUM(PID=3) P3 
FROM
   sales
LEFT JOIN 
   user
ON 
   user.UID = sales.UID
GROUP BY 
   sales.UID
HAVING 
   P1+P2+P3 >= 3
ORDER BY 
   P1 DESC, P2 DESC, P3 DESC;

这是 sqlfiddle 示例，它显示了它的实际效果 - http://sqlfiddle.com/#!2/d3405/8

于 2013-07-13T02:41:03.820 回答