我对PowerShell之间echo
的区别感到困惑。Write-Host
我有两个文件,POC.ps1
& validatePath.ps1
。这些文件在我的本地机器上,我正在使用Invoke-Command
. 我正在使用 PowerShell v3.0。
要执行这两个脚本,我使用以下命令:
.\POC.ps1 -filename C:\Users -user Blaine
这是两个文件:
POC.ps1:
param($filename, $user)
echo $filename
echo "This"
echo $user
$responseObject = Invoke-Command testcomputer -FilePath .\validatePath.ps1 -ArgumentList($filename, $user) -AsJob
while($responseObject.State -ne "Completed")
{
}
$result = Receive-Job -Id $responseObject.Id -Keep
echo $result
这就是事情变得奇怪的地方......
验证路径.ps1:
Param([string] $filename,
[string] $user)
function ValidatePath( $filename, $user, $fileType = "container" )
{
Write-Host "This is the file name: $filename"
Write-Host "This is user: $user" <--- Notice I'm using Write-Host here
$fileExist = $null
if( -not (test-path $filename -PathType $fileType) )
{
throw "$user, the path $filename does not exist!"
}
else
{
Write-Host "This is the second part"
echo $filename found!
}
Write-Host "This is the third part"
return $fileExist
}
try
{
ValidatePath($filename, $user)
}
catch
{
$e = $_.Exception
echo $e
}
当我运行上面的脚本时,这是输出:
C:\Users
This
Blaine
This is the file name: C:\Users Blaine
This is user: <--- Notice where this line is?
This is the second part
This is the third part
C:\Users
Blaine
found!
但是,如果我将其更改validatePath.ps1
为:
Param([string] $filename,
[string] $user)
function ValidatePath( $filename, $user, $fileType = "container" )
{
Write-Host "This is the file name: $filename"
echo "This is user: $user" <---notice I'm using Echo here
$fileExist = $null
if( -not (test-path $filename -PathType $fileType) )
{
throw "$user, the path $filename does not exist!"
}
else
{
Write-Host "This is the second part"
echo $filename found!
}
Write-Host "This is the third part"
return $fileExist
}
try
{
ValidatePath($filename, $user)
}
catch
{
$e = $_.Exception
echo $e
}
这是输出:
C:\Users
This
Blaine
This is the file name: C:\Users Blaine
This is the second part
This is the third part
This is user: <---- Notice where this line is now?
C:\Users
Blaine
found!
您会注意到“这是用户:”这一行位于不同的位置。为什么是这样?为什么echo
工作方式与 不同Write-Host
?
更新:
更奇怪的是,如果我像这样重新运行脚本两次:
POC.ps1:
param($filename, $user)
echo $filename
echo "This"
echo $user
$responseObject = Invoke-Command CAPTESTPK01 -FilePath .\validatePath.ps1 -ArgumentList $filename, $user -AsJob
while($responseObject.State -ne "Completed")
{
}
$result = Receive-Job -Id $responseObject.Id -Keep
echo $result
$filename = "C:\saddfasdfj"
#Here I run the command again, using a different file name
$responseObject = Invoke-Command CAPTESTPK01 -FilePath .\validatePath.ps1 -ArgumentList $filename, $user -AsJob
while($responseObject.State -ne "Completed")
{
if($responseObject.State -eq "Failed")
{
echo "Failed"
$result = Receive-Job -Id $responseObject.Id -Keep
echo $result
break
}
}
$result = Receive-Job -Id $responseObject.Id -Keep
echo $resul
echo
在使用时它给了我这个输出validatePath.ps1
:
C:\Users
This
Blaine
This is the file name: C:\Users
This is the second part
This is the third part
This is user: Blaine <---- This line is here
C:\Users
found!
This is the file name: C:\saddfasdfj
This is user: Blaine <---- But now it's here, where it should be? Wth?
Blaine, the path C:\saddfasdfj does not exist!