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我想给http://www.cleartrip.com/places/hotels/info/41748打一个安静的网络服务电话

如何在请求字符串中形成动态属性?以下是我尝试过但不起作用的方法:

Client client = ClientBuilder.newClient();
client.property("hotelnr", 41748);

//works not (HTTP 404 Not Found):
client.target("http://www.cleartrip.com/places/hotels/info/{hotelnr}").request(MediaType.APPLICATION_XML).get();

//works:
client.target("http://www.cleartrip.com/places/hotels/info/41748").request(MediaType.APPLICATION_XML).get();
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1 回答 1

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看看:http ://docs.oracle.com/javaee/7/tutorial/doc/jaxrs-client001.htm#sthref1397

您可以执行以下操作:

WebTarget myResource = client.target("http://example.com/webapi/read")
  .path("{userName}");
Response response = myResource.queryParam("userName", "janedoe")
  .request(...)
  .get();
于 2013-07-12T12:38:48.323 回答