0

所以我有这个数组data，我想编码有点像[lojas, raparacoes, valor],[nome_1, count_1, val_1],[nome_2, count_2, val_2], etc, etc...

lojas,reparacoes就像valor标题

nome_*来自$row['nome']

count_*来自intval($row['COUNT( DISTINCT id_reparacao )'])

val_*来自intval($row2['SUM(valor)'])

$data = array(array('Lojas'), array('Reparacoes'), array('Valor'));
$qry=mysql_query ('SELECT COUNT( DISTINCT id_reparacao ) , lojas.nome, lojas.id
FROM reparacoes
INNER JOIN lojas ON lojas.id = id_loja 
GROUP BY lojas.id ');

        while($row = mysql_fetch_array($qry))
        {
            $qry2=mysql_query ('SELECT SUM(valor) FROM re_servicos where id_reparacao=(select id_reparacao from reparacoes where id_loja='.$row['id'].' and estado="Fechada")');
            while($row2 = mysql_fetch_array($qry2))
                {
                    $data=[$row['nome'],intval($row['COUNT( DISTINCT id_reparacao )']), intval($row2['SUM(valor)'])];   
                }
        }

但是，使用此代码，我没有在数组中获得所需的输出，我想问题是我填充它的方式，但我不知道如何正确填充它，所以它得到了我在第一段中发布的输出。

PS：我不知道它是否重要但为了更好地理解，我需要这个数组来构建一个谷歌条形图

4

1 回答 1

1

你可以试试这段代码。

 $data = array();
$data[] = array('Lojas', 'Reparacoes', 'Valor');
$qry=mysql_query ('SELECT COUNT( DISTINCT id_reparacao ) , lojas.nome, lojas.id
FROM reparacoes
INNER JOIN lojas ON lojas.id = id_loja 
GROUP BY lojas.id ');

        while($row = mysql_fetch_array($qry))
        {
            $qry2=mysql_query ('SELECT SUM(valor) FROM re_servicos where id_reparacao=(select id_reparacao from reparacoes where id_loja='.$row['id'].' and estado="Fechada")');
            while($row2 = mysql_fetch_array($qry2))
                {
                    $data[]=array($row['nome'],intval($row['COUNT( DISTINCT id_reparacao )']), intval($row2['SUM(valor)']));   
                }
        }
于 2013-07-12T10:17:36.773 回答