sql - 从 SQL Server 表中的 varchar 列获取子字符串

Question

我有一列名为名称，在列中我有值

Name
001 BASI Distributor (EXAM)
002 BASI Supplier (EXAM2)
MASI DISTRIBUTOR (EXAM002)
MASI SUPPLIER (EXAM003)
EXAM_ND Distributor Success System Test (EXAM_ND)
EXAM_SS Supplier Success System Test (EXAM_SS)

现在我想将 中的值与()整个字符串分开。我将如何得到这个我尝试过，SUBSTRING (Name ,22 ,4 )但这将有助于我想使用一些独特的解决方案获得结果的单个人。

Answer 1

SELECT  SUBSTRING(Name,
        CHARINDEX('(', Name) + 1,
        CHARINDEX(')', Name) - CHARINDEX('(', Name) - 1)

Answer 2

另一种选择：

SELECT *, REPLACE(SUBSTRING(Name, CHARINDEX('(', Name) + 1, LEN(Name)), ')', '')
FROM dbo.test136

假设您的值在括号部分之后不包含任何内容，这可以节省一个CHARINDEX电话（搜索结束）。如果他们这样做，请使用其他建议。)Name

Answer 3

试试这个——

DECLARE @temp TABLE (st NVARCHAR(50))

INSERT INTO @temp (st)
VALUES 
     ('001 BASI Distributor (EXAM)'),
     ('002 BASI Supplier (EXAM2)'),
     ('MASI DISTRIBUTOR (EXAM002)'),
     ('MASI SUPPLIER (EXAM003)'),
     ('EXAM_ND Distributor Success System Test (EXAM_ND)'),
     ('EXAM_SS Supplier Success System Test (EXAM_SS)')

SELECT SUBSTRING(
     st, 
     CHARINDEX('(', st) + 1, 
     CHARINDEX(')', st) - CHARINDEX('(', st) - 1
)
FROM @temp

输出 -

-------------
EXAM
EXAM2
EXAM002
EXAM003
EXAM_ND
EXAM_SS

Answer 4

请试试：

SELECT 
    REPLACE(SUBSTRING(Name, PATINDEX('%(%', Name)+1, LEN(Name)), ')', '')
FROM 
    YourTable